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CH3NH2(0.12 mole,pKb=3.3) is added to 0.08 moles of HCl and the solution is diluted to on litre, resulting pH of solution is : (A)10.7 (B)3.6. (C)10.4. (D)11.3?
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CH3NH2(0.12 mole,pKb=3.3) is added to 0.08 moles of HCl and the soluti...
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CH3NH2(0.12 mole,pKb=3.3) is added to 0.08 moles of HCl and the soluti...
Calculating the pH of a Solution containing CH3NH2 and HCl
Given:
- Amount of CH3NH2 (methylamine) = 0.12 moles
- Amount of HCl = 0.08 moles
- pKb of CH3NH2 = 3.3
- Total volume of the solution = 1 L
Step 1: Write the chemical equation for the reaction between CH3NH2 and HCl.
CH3NH2 + HCl → CH3NH3+ Cl-
Step 2: Calculate the concentration of CH3NH2 and CH3NH3+ in the solution.
- Concentration of CH3NH2 = 0.12 M
- Concentration of CH3NH3+ = concentration of HCl = 0.08 M
Step 3: Calculate the Kb value of CH3NH2.
pKb + pKa = 14
pKa = 14 - pKb = 14 - 3.3 = 10.7
Ka = 10^-pKa = 10^-10.7
Kb = Kw/Ka = 10^-14/10^-10.7 = 10^-3.3
Step 4: Calculate the concentration of OH- ions.
Kb = [CH3NH2][OH-]/[CH3NH3+]
[OH-] = Kb[CH3NH3+]/[CH3NH2] = 10^-3.3 * 0.08/0.12 = 5.33 * 10^-4
Step 5: Calculate the pH of the solution.
pH = 14 - pOH = 14 - (-log[OH-]) = 14 - (-log5.33 * 10^-4) = 10.4
Therefore, the pH of the solution is 10.4, which is option (C).
Given:
- Amount of CH3NH2 (methylamine) = 0.12 moles
- Amount of HCl = 0.08 moles
- pKb of CH3NH2 = 3.3
- Total volume of the solution = 1 L
Step 1: Write the chemical equation for the reaction between CH3NH2 and HCl.
CH3NH2 + HCl → CH3NH3+ Cl-
Step 2: Calculate the concentration of CH3NH2 and CH3NH3+ in the solution.
- Concentration of CH3NH2 = 0.12 M
- Concentration of CH3NH3+ = concentration of HCl = 0.08 M
Step 3: Calculate the Kb value of CH3NH2.
pKb + pKa = 14
pKa = 14 - pKb = 14 - 3.3 = 10.7
Ka = 10^-pKa = 10^-10.7
Kb = Kw/Ka = 10^-14/10^-10.7 = 10^-3.3
Step 4: Calculate the concentration of OH- ions.
Kb = [CH3NH2][OH-]/[CH3NH3+]
[OH-] = Kb[CH3NH3+]/[CH3NH2] = 10^-3.3 * 0.08/0.12 = 5.33 * 10^-4
Step 5: Calculate the pH of the solution.
pH = 14 - pOH = 14 - (-log[OH-]) = 14 - (-log5.33 * 10^-4) = 10.4
Therefore, the pH of the solution is 10.4, which is option (C).
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CH3NH2(0.12 mole,pKb=3.3) is added to 0.08 moles of HCl and the solution is diluted to on litre, resulting pH of solution is : (A)10.7 (B)3.6. (C)10.4. (D)11.3?
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CH3NH2(0.12 mole,pKb=3.3) is added to 0.08 moles of HCl and the solution is diluted to on litre, resulting pH of solution is : (A)10.7 (B)3.6. (C)10.4. (D)11.3? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about CH3NH2(0.12 mole,pKb=3.3) is added to 0.08 moles of HCl and the solution is diluted to on litre, resulting pH of solution is : (A)10.7 (B)3.6. (C)10.4. (D)11.3? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for CH3NH2(0.12 mole,pKb=3.3) is added to 0.08 moles of HCl and the solution is diluted to on litre, resulting pH of solution is : (A)10.7 (B)3.6. (C)10.4. (D)11.3?.
CH3NH2(0.12 mole,pKb=3.3) is added to 0.08 moles of HCl and the solution is diluted to on litre, resulting pH of solution is : (A)10.7 (B)3.6. (C)10.4. (D)11.3? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about CH3NH2(0.12 mole,pKb=3.3) is added to 0.08 moles of HCl and the solution is diluted to on litre, resulting pH of solution is : (A)10.7 (B)3.6. (C)10.4. (D)11.3? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for CH3NH2(0.12 mole,pKb=3.3) is added to 0.08 moles of HCl and the solution is diluted to on litre, resulting pH of solution is : (A)10.7 (B)3.6. (C)10.4. (D)11.3?.
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CH3NH2(0.12 mole,pKb=3.3) is added to 0.08 moles of HCl and the solution is diluted to on litre, resulting pH of solution is : (A)10.7 (B)3.6. (C)10.4. (D)11.3?, a detailed solution for CH3NH2(0.12 mole,pKb=3.3) is added to 0.08 moles of HCl and the solution is diluted to on litre, resulting pH of solution is : (A)10.7 (B)3.6. (C)10.4. (D)11.3? has been provided alongside types of CH3NH2(0.12 mole,pKb=3.3) is added to 0.08 moles of HCl and the solution is diluted to on litre, resulting pH of solution is : (A)10.7 (B)3.6. (C)10.4. (D)11.3? theory, EduRev gives you an
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