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The potential energy of a particle executing simple harmonic motion from a distance x from its equilibrium position is
- a)1/2 mω2x2
- b)1/2 mω2a2
- c)1/2 mω2(a2x2)
- d)Zero
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
The potential energy of a particle executing simple harmonic motion fr...
Ω²x²
b)1/2 kx²
c)1/2 mv²
d)1/2 kA²
The correct answer is b) 1/2 kx².
Explanation:
The potential energy of a particle executing simple harmonic motion is given by the formula:
U = 1/2 kx²
where k is the spring constant and x is the displacement of the particle from its equilibrium position.
This formula represents the potential energy stored in the spring when it is stretched or compressed from its equilibrium position. The potential energy is maximum when the displacement is maximum (i.e., at the extreme points of the motion) and zero when the particle is at its equilibrium position.
Option a) is incorrect because it only gives the square of the amplitude, but not the spring constant.
Option c) is incorrect because it gives the kinetic energy, not the potential energy.
Option d) is incorrect because A represents the amplitude of the motion, not the displacement from the equilibrium position.
b)1/2 kx²
c)1/2 mv²
d)1/2 kA²
The correct answer is b) 1/2 kx².
Explanation:
The potential energy of a particle executing simple harmonic motion is given by the formula:
U = 1/2 kx²
where k is the spring constant and x is the displacement of the particle from its equilibrium position.
This formula represents the potential energy stored in the spring when it is stretched or compressed from its equilibrium position. The potential energy is maximum when the displacement is maximum (i.e., at the extreme points of the motion) and zero when the particle is at its equilibrium position.
Option a) is incorrect because it only gives the square of the amplitude, but not the spring constant.
Option c) is incorrect because it gives the kinetic energy, not the potential energy.
Option d) is incorrect because A represents the amplitude of the motion, not the displacement from the equilibrium position.
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The potential energy of a particle executing simple harmonic motion from a distance x from its equilibrium position isa)1/2 mω2x2b)1/2 mω2a2c)1/2 mω2(a2x2)d)ZeroCorrect answer is option 'A'. Can you explain this answer?
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