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Sodium carbonate cannot be used in place of ammonium carbonate for the identification of the fifth group radicals . This is because the
  • a)
    Sodium ions will interfere in the detection of the fifth group radicals
  • b)
    Concentration of carbonate ions is very low
  • c)
    Sodium will react with acidic radicals
  • d)
    Magnisium will be precipitated
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Sodium carbonate cannot be used in place of ammonium carbonate for the...
Reasoning:

The identification of fifth group radicals (arsenate, antimonate, and phosphate ions) can be done by adding ammonium carbonate (NH4)2CO3. The addition of ammonium carbonate forms precipitates of corresponding metal carbonates. However, sodium carbonate cannot be used in place of ammonium carbonate for this purpose. This is because sodium ions will interfere in the detection of the fifth group radicals.

Explanation:

Ammonium carbonate is a white crystalline solid having the chemical formula (NH4)2CO3. When it is added to a solution containing fifth group radicals, it reacts with them to form corresponding metal carbonates. For example, arsenate ions (AsO4^3-) react with ammonium carbonate to form arsenate (As2O5) and ammonium bicarbonate (NH4HCO3).

(NH4)2CO3 + AsO4^3- → As2O5 + NH4HCO3

The precipitate of metal carbonate formed can be used to identify the fifth group radicals.

On the other hand, sodium carbonate (Na2CO3) also reacts with fifth group radicals to form corresponding metal carbonates. However, sodium ions present in the sodium carbonate solution interfere in the detection of fifth group radicals. Sodium ions form a white precipitate with ammonium molybdate, which is used as a reagent for the detection of fifth group radicals. This white precipitate may mask the formation of metal carbonate precipitates, making it difficult to identify the fifth group radicals.

Conclusion:

Sodium carbonate cannot be used in place of ammonium carbonate for the identification of fifth group radicals because sodium ions interfere in the detection of the fifth group radicals.
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Community Answer
Sodium carbonate cannot be used in place of ammonium carbonate for the...
Na2CO3 is highly ionised electrolyte, which produces very high cone, of CO32- ions. As a result ionic product of MgCO3 may increase its Ksp and it may get precipitated along with the radicals of V group.

Hope this answer will help you!!
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Sodium carbonate cannot be used in place of ammonium carbonate for the identification of the fifth group radicals . This is because thea)Sodium ions will interfere in the detection of the fifth group radicalsb)Concentration of carbonate ions is very lowc)Sodium will react with acidic radicalsd)Magnisium will be precipitatedCorrect answer is option 'A'. Can you explain this answer?
Question Description
Sodium carbonate cannot be used in place of ammonium carbonate for the identification of the fifth group radicals . This is because thea)Sodium ions will interfere in the detection of the fifth group radicalsb)Concentration of carbonate ions is very lowc)Sodium will react with acidic radicalsd)Magnisium will be precipitatedCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Sodium carbonate cannot be used in place of ammonium carbonate for the identification of the fifth group radicals . This is because thea)Sodium ions will interfere in the detection of the fifth group radicalsb)Concentration of carbonate ions is very lowc)Sodium will react with acidic radicalsd)Magnisium will be precipitatedCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Sodium carbonate cannot be used in place of ammonium carbonate for the identification of the fifth group radicals . This is because thea)Sodium ions will interfere in the detection of the fifth group radicalsb)Concentration of carbonate ions is very lowc)Sodium will react with acidic radicalsd)Magnisium will be precipitatedCorrect answer is option 'A'. Can you explain this answer?.
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