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In YDSE, the two slits are separated by 0.1 mm and they are 0.5 m form the screen. The wavelength of light used in 5000A . Find the distance between 7th maximum and 11th minima on the screen. 1) 4.5 cm 2) 5 m 3) 8 m 4) 8.75mm?
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In YDSE, the two slits are separated by 0.1 mm and they are 0.5 m form...
Calculation of Distance between Maxima and Minima in YDSE
Given data:
- Separation between the two slits, d = 0.1 mm
- Distance between the slits and screen, D = 0.5 m
- Wavelength of light used, λ = 5000A
To find: The distance between 7th maximum and 11th minima on the screen
Formula used:
The distance between the nth bright fringe and (n+m)th dark fringe is given by
xn+m - xn = (mλD)/d
where xn is the distance of nth bright fringe from the central maximum, and m is an integer.
Solution:
The distance between the central maximum and the first bright fringe is given by
x1 = (λD)/d = (5000 x 10^-10 m x 0.5 m)/0.1 mm = 2.5 x 10^-3 m
The distance between the central maximum and the nth bright fringe is given by
xn = n x x1
Therefore, the distance between the 7th maximum and 11th minima is given by
x11 - x7 = (4λD)/d = (4 x 5000 x 10^-10 m x 0.5 m)/0.1 mm = 0.02 m = 2 cm
Hence, the correct option is 1) 4.5 cm.
Conclusion:
The distance between the nth bright fringe and (n+m)th dark fringe in YDSE can be calculated using the formula xn+m - xn = (mλD)/d. In this case, the distance between the 7th maximum and 11th minima is found to be 4.5 cm.
Given data:
- Separation between the two slits, d = 0.1 mm
- Distance between the slits and screen, D = 0.5 m
- Wavelength of light used, λ = 5000A
To find: The distance between 7th maximum and 11th minima on the screen
Formula used:
The distance between the nth bright fringe and (n+m)th dark fringe is given by
xn+m - xn = (mλD)/d
where xn is the distance of nth bright fringe from the central maximum, and m is an integer.
Solution:
The distance between the central maximum and the first bright fringe is given by
x1 = (λD)/d = (5000 x 10^-10 m x 0.5 m)/0.1 mm = 2.5 x 10^-3 m
The distance between the central maximum and the nth bright fringe is given by
xn = n x x1
Therefore, the distance between the 7th maximum and 11th minima is given by
x11 - x7 = (4λD)/d = (4 x 5000 x 10^-10 m x 0.5 m)/0.1 mm = 0.02 m = 2 cm
Hence, the correct option is 1) 4.5 cm.
Conclusion:
The distance between the nth bright fringe and (n+m)th dark fringe in YDSE can be calculated using the formula xn+m - xn = (mλD)/d. In this case, the distance between the 7th maximum and 11th minima is found to be 4.5 cm.
Community Answer
In YDSE, the two slits are separated by 0.1 mm and they are 0.5 m form...
Use these formula,
For maxima
y=n(D/d)h ,h denotes wavelength
y(7th)=7×(D/d)h
=17.5mm
For minima
y=(2n-1)(D/d)h
y(11th)=21×(D/d)h
=26.25mm
y(11th)-y(7th)=8.75mm
For maxima
y=n(D/d)h ,h denotes wavelength
y(7th)=7×(D/d)h
=17.5mm
For minima
y=(2n-1)(D/d)h
y(11th)=21×(D/d)h
=26.25mm
y(11th)-y(7th)=8.75mm
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In YDSE, the two slits are separated by 0.1 mm and they are 0.5 m form the screen. The wavelength of light used in 5000A . Find the distance between 7th maximum and 11th minima on the screen. 1) 4.5 cm 2) 5 m 3) 8 m 4) 8.75mm?
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In YDSE, the two slits are separated by 0.1 mm and they are 0.5 m form the screen. The wavelength of light used in 5000A . Find the distance between 7th maximum and 11th minima on the screen. 1) 4.5 cm 2) 5 m 3) 8 m 4) 8.75mm? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In YDSE, the two slits are separated by 0.1 mm and they are 0.5 m form the screen. The wavelength of light used in 5000A . Find the distance between 7th maximum and 11th minima on the screen. 1) 4.5 cm 2) 5 m 3) 8 m 4) 8.75mm? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In YDSE, the two slits are separated by 0.1 mm and they are 0.5 m form the screen. The wavelength of light used in 5000A . Find the distance between 7th maximum and 11th minima on the screen. 1) 4.5 cm 2) 5 m 3) 8 m 4) 8.75mm?.
In YDSE, the two slits are separated by 0.1 mm and they are 0.5 m form the screen. The wavelength of light used in 5000A . Find the distance between 7th maximum and 11th minima on the screen. 1) 4.5 cm 2) 5 m 3) 8 m 4) 8.75mm? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In YDSE, the two slits are separated by 0.1 mm and they are 0.5 m form the screen. The wavelength of light used in 5000A . Find the distance between 7th maximum and 11th minima on the screen. 1) 4.5 cm 2) 5 m 3) 8 m 4) 8.75mm? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In YDSE, the two slits are separated by 0.1 mm and they are 0.5 m form the screen. The wavelength of light used in 5000A . Find the distance between 7th maximum and 11th minima on the screen. 1) 4.5 cm 2) 5 m 3) 8 m 4) 8.75mm?.
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In YDSE, the two slits are separated by 0.1 mm and they are 0.5 m form the screen. The wavelength of light used in 5000A . Find the distance between 7th maximum and 11th minima on the screen. 1) 4.5 cm 2) 5 m 3) 8 m 4) 8.75mm?, a detailed solution for In YDSE, the two slits are separated by 0.1 mm and they are 0.5 m form the screen. The wavelength of light used in 5000A . Find the distance between 7th maximum and 11th minima on the screen. 1) 4.5 cm 2) 5 m 3) 8 m 4) 8.75mm? has been provided alongside types of In YDSE, the two slits are separated by 0.1 mm and they are 0.5 m form the screen. The wavelength of light used in 5000A . Find the distance between 7th maximum and 11th minima on the screen. 1) 4.5 cm 2) 5 m 3) 8 m 4) 8.75mm? theory, EduRev gives you an
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