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Which of the following does not produce a white precipitate of AgCl on warming with alcoholic silver
nitrate ?
nitrate ?
- a)Allyl chloride
- b)t-Butyl chloride
- c)Benzyl chloride
- d)Vinyl chloride
Correct answer is option 'D'. Can you explain this answer?
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Which of the following does not produce a white precipitate of AgCl on...
Aryl and vinyl halide's are not hydrolysed by alcoholic silver nitrate solution. Therefore,
Vinyl chloride does not produce a white precipitate of AgCl on warming with alcoholic silver nitrate .
Vinyl chloride does not produce a white precipitate of AgCl on warming with alcoholic silver nitrate .
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Which of the following does not produce a white precipitate of AgCl on...
Answer:
Vinyl chloride does not produce a white precipitate of AgCl on warming with alcoholic silver nitrate.
Explanation:
Vinyl chloride is a primary alkyl halide and has the formula CH2=CHCl. It is an unsaturated compound, i.e., it contains a double bond between carbon and carbon. When it is treated with alcoholic silver nitrate, it does not undergo nucleophilic substitution reaction as it is not an alkyl halide. The double bond present in the molecule is responsible for the resistance to nucleophilic substitution.
On the other hand, the other three options, i.e., allyl chloride, t-butyl chloride, and benzyl chloride, are alkyl halides. When they are treated with alcoholic silver nitrate, they undergo nucleophilic substitution reaction and produce a white precipitate of AgCl on warming.
Allyl chloride and benzyl chloride have a reactive group attached to the alkyl chain, which makes them more susceptible to nucleophilic substitution. t-Butyl chloride is a tertiary alkyl halide, which is known to undergo nucleophilic substitution reaction slowly. However, on warming with alcoholic silver nitrate, it forms a white precipitate of AgCl.
Therefore, the correct answer is option D, i.e., vinyl chloride, as it does not produce a white precipitate of AgCl on warming with alcoholic silver nitrate due to its unsaturated nature.
Vinyl chloride does not produce a white precipitate of AgCl on warming with alcoholic silver nitrate.
Explanation:
Vinyl chloride is a primary alkyl halide and has the formula CH2=CHCl. It is an unsaturated compound, i.e., it contains a double bond between carbon and carbon. When it is treated with alcoholic silver nitrate, it does not undergo nucleophilic substitution reaction as it is not an alkyl halide. The double bond present in the molecule is responsible for the resistance to nucleophilic substitution.
On the other hand, the other three options, i.e., allyl chloride, t-butyl chloride, and benzyl chloride, are alkyl halides. When they are treated with alcoholic silver nitrate, they undergo nucleophilic substitution reaction and produce a white precipitate of AgCl on warming.
Allyl chloride and benzyl chloride have a reactive group attached to the alkyl chain, which makes them more susceptible to nucleophilic substitution. t-Butyl chloride is a tertiary alkyl halide, which is known to undergo nucleophilic substitution reaction slowly. However, on warming with alcoholic silver nitrate, it forms a white precipitate of AgCl.
Therefore, the correct answer is option D, i.e., vinyl chloride, as it does not produce a white precipitate of AgCl on warming with alcoholic silver nitrate due to its unsaturated nature.
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Which of the following does not produce a white precipitate of AgCl on warming with alcoholic silvernitrate ?a)Allyl chlorideb) t-Butyl chloridec)Benzyl chlorided) Vinyl chlorideCorrect answer is option 'D'. Can you explain this answer?
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