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Standard electrode potentials given as, Mg2 /Mg = −2.37 V, Hg2 /Hg = 0.79V, Cr3 /Cr = − 0.74V, Ag /Ag = 0.80V, K /K = −2.93V In the order of increasing of reducing power arrange the given metals accordingly.?
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Standard electrode potentials given as, Mg2 /Mg = −2.37 V, Hg2 /Hg = 0...

Arranging Metals in Order of Increasing Reducing Power:

The reducing power of a metal can be determined by its standard electrode potential. A metal with a more negative standard electrode potential will have a higher reducing power. In this case, we have the following standard electrode potentials:

- Mg2+/Mg = -2.37 V
- Hg2+/Hg = 0.79 V
- Cr3+/Cr = -0.74 V
- Ag/Ag = 0.80 V
- K/K = -2.93 V

To arrange the metals in order of increasing reducing power, we need to consider their standard electrode potentials. The metal with the least negative (or most positive) standard electrode potential will have the lowest reducing power, while the metal with the most negative standard electrode potential will have the highest reducing power.

Arranging the Metals:
1. Potassium (K): K/K = -2.93 V
- Potassium has the most negative standard electrode potential, indicating the highest reducing power.

2. Magnesium (Mg): Mg2+/Mg = -2.37 V
- Magnesium has a less negative standard electrode potential compared to potassium, indicating a lower reducing power than potassium.

3. Chromium (Cr): Cr3+/Cr = -0.74 V
- Chromium has a less negative standard electrode potential compared to magnesium, indicating a lower reducing power than magnesium.

4. Silver (Ag): Ag/Ag = 0.80 V
- Silver has a positive standard electrode potential, indicating a lower reducing power than chromium.

5. Mercury (Hg): Hg2+/Hg = 0.79 V
- Mercury has a slightly lower positive standard electrode potential compared to silver, indicating the lowest reducing power among the metals.

Summary:
- The metals arranged in increasing order of reducing power are: Mercury (Hg) < silver="" (ag)="" />< chromium="" (cr)="" />< magnesium="" (mg)="" />< potassium="" />
- Potassium has the highest reducing power, while mercury has the lowest reducing power.
- The reducing power of a metal is determined by its standard electrode potential, with more negative values indicating higher reducing power.
Community Answer
Standard electrode potentials given as, Mg2 /Mg = −2.37 V, Hg2 /Hg = 0...
K+>mg2+>cr3+>hg2+>ag+
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Standard electrode potentials given as, Mg2 /Mg = −2.37 V, Hg2 /Hg = 0.79V, Cr3 /Cr = − 0.74V, Ag /Ag = 0.80V, K /K = −2.93V In the order of increasing of reducing power arrange the given metals accordingly.?
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Standard electrode potentials given as, Mg2 /Mg = −2.37 V, Hg2 /Hg = 0.79V, Cr3 /Cr = − 0.74V, Ag /Ag = 0.80V, K /K = −2.93V In the order of increasing of reducing power arrange the given metals accordingly.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Standard electrode potentials given as, Mg2 /Mg = −2.37 V, Hg2 /Hg = 0.79V, Cr3 /Cr = − 0.74V, Ag /Ag = 0.80V, K /K = −2.93V In the order of increasing of reducing power arrange the given metals accordingly.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Standard electrode potentials given as, Mg2 /Mg = −2.37 V, Hg2 /Hg = 0.79V, Cr3 /Cr = − 0.74V, Ag /Ag = 0.80V, K /K = −2.93V In the order of increasing of reducing power arrange the given metals accordingly.?.
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