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The correct order of the decreasing ionic radii among the following isoelectronic species is
- a)Ca2+ > K+ > S2 >Cl-
- b)Cl- > S2- > Ca2+ > K+
- c)S2- > Cl- > K+ > Ca2+
- d)K+ > Ca+ > Cl- >S2-
Correct answer is option 'C'. Can you explain this answer?
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The correct order of the decreasing ionic radii among the following is...
In the cation formation, valence electrons are lost while in anion formation, electrons add to the valence electrons. If in each species the numbers of electrons are the same, the higher the nuclear change, smaller is the ionic radius. The option (c) is correct
Most Upvoted Answer
The correct order of the decreasing ionic radii among the following is...
Comparing S²- and Cl- ...
Originally, the atomic radii of Sulphur is greater than that of Chlorine and by gaining two electrons its radius increases more while chlorine gas gained only one electron. Thus S²- > Cl- .
Comparing K+ and Ca²+ ....
Originally, the atomic size of Potassium is more than that of Calcium. After losing one electron size of Potassium decreases but Calcium whose size was smaller, losses two electrons and its size decreases even more. Thus K+ > Ca²+ .
These two results can only be seen in option c
Originally, the atomic radii of Sulphur is greater than that of Chlorine and by gaining two electrons its radius increases more while chlorine gas gained only one electron. Thus S²- > Cl- .
Comparing K+ and Ca²+ ....
Originally, the atomic size of Potassium is more than that of Calcium. After losing one electron size of Potassium decreases but Calcium whose size was smaller, losses two electrons and its size decreases even more. Thus K+ > Ca²+ .
These two results can only be seen in option c
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The correct order of the decreasing ionic radii among the following is...
Size of isoelectronic species follows a order that higher atomic no element will be smallest due to highest Effective nuclear charge
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The correct order of the decreasing ionic radii among the following isoelectronic species isa)Ca2+> K+> S2>Cl-b)Cl-> S2-> Ca2+> K+c)S2- > Cl-> K+ > Ca2+d)K+ > Ca+ > Cl- >S2-Correct answer is option 'C'. Can you explain this answer?
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The correct order of the decreasing ionic radii among the following isoelectronic species isa)Ca2+> K+> S2>Cl-b)Cl-> S2-> Ca2+> K+c)S2- > Cl-> K+ > Ca2+d)K+ > Ca+ > Cl- >S2-Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The correct order of the decreasing ionic radii among the following isoelectronic species isa)Ca2+> K+> S2>Cl-b)Cl-> S2-> Ca2+> K+c)S2- > Cl-> K+ > Ca2+d)K+ > Ca+ > Cl- >S2-Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The correct order of the decreasing ionic radii among the following isoelectronic species isa)Ca2+> K+> S2>Cl-b)Cl-> S2-> Ca2+> K+c)S2- > Cl-> K+ > Ca2+d)K+ > Ca+ > Cl- >S2-Correct answer is option 'C'. Can you explain this answer?.
The correct order of the decreasing ionic radii among the following isoelectronic species isa)Ca2+> K+> S2>Cl-b)Cl-> S2-> Ca2+> K+c)S2- > Cl-> K+ > Ca2+d)K+ > Ca+ > Cl- >S2-Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The correct order of the decreasing ionic radii among the following isoelectronic species isa)Ca2+> K+> S2>Cl-b)Cl-> S2-> Ca2+> K+c)S2- > Cl-> K+ > Ca2+d)K+ > Ca+ > Cl- >S2-Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The correct order of the decreasing ionic radii among the following isoelectronic species isa)Ca2+> K+> S2>Cl-b)Cl-> S2-> Ca2+> K+c)S2- > Cl-> K+ > Ca2+d)K+ > Ca+ > Cl- >S2-Correct answer is option 'C'. Can you explain this answer?.
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