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The electric field intensity of the surface of a solid charged sphere of radius r and volume charge density ρ, is given by
- a)ρr/ε₀
- b)ρr/3ε₀
- c)5ρr/6ε₀
- d)ρ/4πε₀r
Correct answer is option 'B'. Can you explain this answer?
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The electric field intensity of the surface of a solid charged sphere ...
Ρ is given by:
E = ρr / (3ε)
where ε is the electric permittivity of the surrounding medium. This formula assumes that the sphere is uniformly charged.
If the sphere is not uniformly charged, the electric field intensity at any point outside the sphere can be found using Coulomb's law, which states that the electric field intensity at a point due to a point charge Q is given by:
E = kQ / r^2
where k is the Coulomb constant (8.9876 x 10^9 N m^2/C^2) and r is the distance from the point charge to the point at which the electric field intensity is being calculated. The total electric field intensity at a point outside the sphere due to all the charges on the sphere can be found by summing up the contributions from each point charge on the sphere using vector addition.
Inside the sphere, the electric field intensity is zero due to the symmetry of the charge distribution.
E = ρr / (3ε)
where ε is the electric permittivity of the surrounding medium. This formula assumes that the sphere is uniformly charged.
If the sphere is not uniformly charged, the electric field intensity at any point outside the sphere can be found using Coulomb's law, which states that the electric field intensity at a point due to a point charge Q is given by:
E = kQ / r^2
where k is the Coulomb constant (8.9876 x 10^9 N m^2/C^2) and r is the distance from the point charge to the point at which the electric field intensity is being calculated. The total electric field intensity at a point outside the sphere due to all the charges on the sphere can be found by summing up the contributions from each point charge on the sphere using vector addition.
Inside the sphere, the electric field intensity is zero due to the symmetry of the charge distribution.
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The electric field intensity of the surface of a solid charged sphere ...
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The electric field intensity of the surface of a solid charged sphere of radius r and volume charge density ρ, is given bya)ρr/εb)ρr/3εc)5ρr/6εd)ρ/4πεrCorrect answer is option 'B'. Can you explain this answer?
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