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The enthalpy of neutralisation of acid acid and sodium hydroxide is -55.4 KJ.What is the enthalpy ionisation of acetic acid ?
  • a)
    -1.9 KJ
  • b)
    + 1.9 KJ
  • c)
    +5.54 KJ
  • d)
    -5.54 KJ
Correct answer is option 'B'. Can you explain this answer?
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The enthalpy of neutralisation of acid acid and sodium hydroxide is -5...
Understanding Enthalpy of Neutralisation
The enthalpy of neutralisation refers to the heat change when an acid reacts with a base to form water and a salt. In this case, acetic acid (CH3COOH) reacts with sodium hydroxide (NaOH).
Given Data
- Enthalpy of neutralisation (ΔH_neutralisation) = -55.4 kJ/mol
Ionisation of Acetic Acid
Acetic acid is a weak acid, meaning it does not completely ionise in water. The reaction can be represented as:
CH3COOH ⇌ CH3COO⁻ + H⁺
To find the enthalpy of ionisation (ΔH_ionisation) of acetic acid, we need to relate it to the enthalpy of neutralisation. The neutralisation reaction can be represented as:
CH3COOH + NaOH → CH3COONa + H2O
Key Relationships
- The enthalpy change for neutralisation is the heat released when the weak acid (acetic acid) ionises and reacts with the strong base (sodium hydroxide).
- Since the ionisation of acetic acid absorbs energy (endothermic), it has a positive enthalpy change.
Calculation Insight
The enthalpy of neutralisation can be expressed as:
ΔH_neutralisation = ΔH_ionisation + ΔH_formation of water
Rearranging gives us:
ΔH_ionisation = ΔH_neutralisation - ΔH_formation of water
Assuming the formation of water is approximately -57.3 kJ/mol, we find:
ΔH_ionisation = -55.4 kJ + 57.3 kJ = +1.9 kJ/mol
Conclusion
Thus, the enthalpy of ionisation of acetic acid is +1.9 kJ/mol, which corresponds to option 'B'. This indicates that energy is required for the ionisation process, aligning with the characteristics of weak acids.
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The enthalpy of neutralisation of acid acid and sodium hydroxide is -55.4 KJ.What is the enthalpy ionisation of acetic acid ?a)-1.9 KJb)+ 1.9 KJc)+5.54 KJd)-5.54 KJCorrect answer is option 'B'. Can you explain this answer?
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