All charge on a conductor must reside on its outer surface.-this state...
Statement Explanation:
The statement "All charge on a conductor must reside on its outer surface" implies that any charge present on a conductor will distribute itself uniformly on the surface of the conductor, and there will be no electric field inside the conductor. This statement is true for all conductors, regardless of their shape and size.
Explanation:
The reason behind this statement is based on the fact that charges on a conductor repel each other, and they naturally try to move as far away from each other as possible. As a result, they will distribute themselves uniformly on the outer surface of the conductor until they reach an electrostatic equilibrium.
This phenomenon is known as the "Faraday's cage effect," which states that any charges present inside a conductor will create an equal and opposite charge on the surface of the conductor, which will cancel out the electric field inside the conductor. Therefore, the electric field inside the conductor is always zero, and all the charges reside on the outer surface of the conductor.
This principle is applicable to all conductors, whether they are spherical or not, and whether they have sharp points or corners. However, sharp points or corners can cause a concentration of charges, which can create a higher electric field in the vicinity of the points or corners. Still, the charge will eventually distribute itself uniformly on the outer surface of the conductor.
Conclusion:
In conclusion, the statement "All charge on a conductor must reside on its outer surface" is true for all conductors, and it is based on the principle of the Faraday's cage effect. This principle is essential in understanding the behavior of conductors in electrostatics and has many practical applications in various fields of science and engineering.
All charge on a conductor must reside on its outer surface.-this state...
I think option C is correct
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