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The radioisotope, tritium (3H₁) has a half-life of 12.3 years. If the initial amount of tritium is 32 mg, how many miligrams of it would remain after 49.2 years ?
  • a)
    2 mg
  • b)
    4 mg
  • c)
    8 mg
  • d)
    1 mg
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The radioisotope, tritium (3H) has a half-life of 12.3 years. If the i...
2 mg

Given half life of Tritium = 12.3 Given time = 49.2. So , the no:of half lives = 49.2/12.3 = 4 Now amount remaining equal to N / 2^n here (^n indicated power to n).
So 32mg / 2^4 = 32 / 16 = 2mg
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Community Answer
The radioisotope, tritium (3H) has a half-life of 12.3 years. If the i...
Given data:
- Half-life of tritium (3H) = 12.3 years
- Initial amount of tritium = 32 mg
- Time after which amount of tritium is to be calculated = 49.2 years

To find: Amount of tritium remaining after 49.2 years

Solution:
Let's first calculate the number of half-lives that have passed in 49.2 years:
Number of half-lives = Time elapsed / Half-life
Number of half-lives = 49.2 / 12.3
Number of half-lives = 4

This means that the initial amount of tritium would have decreased by a factor of 2^4 = 16 (since each half-life reduces the amount to half).
So, the amount of tritium remaining after 49.2 years would be:
Remaining amount = Initial amount / 2^(number of half-lives)
Remaining amount = 32 / 2^4
Remaining amount = 2 mg

Therefore, the correct option is (a) 2 mg.
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The radioisotope, tritium (3H) has a half-life of 12.3 years. If the initial amount of tritium is 32 mg, how many miligrams of it would remain after 49.2 years ?a)2 mgb)4 mgc)8 mgd)1 mgCorrect answer is option 'A'. Can you explain this answer?
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