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a dihybrid plant on self pollination , produced 400 phenotypes with 9 genotypes . How many seeds will have genotype TtRr 1) 200 2) 100 3)50. 4)150
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a dihybrid plant on self pollination , produced 400 phenotypes with 9 ...
Calculation of Seeds with Genotype TtRr
To determine the number of seeds with genotype TtRr produced by the dihybrid plant, we need to consider the principles of Mendelian genetics and the results of the self-pollination.
Genotypes and Phenotypes
The dihybrid plant produced 400 phenotypes with 9 genotypes. This means that there are 9 different combinations of alleles present in the offspring. One of these genotypes is TtRr, which represents a plant heterozygous for both traits.
Dihybrid Cross
In a dihybrid cross, the alleles for each trait segregate independently during gamete formation. This means that the gametes produced by the plant will have all possible combinations of alleles for the two traits.
Punnett Square
By using a Punnett square, we can determine the probability of producing a seed with genotype TtRr. In this case, the probability is 1/16, as there are 16 possible combinations of alleles in the square and only one of them is TtRr.
Calculation
Since the probability of producing a seed with genotype TtRr is 1/16, out of the 400 phenotypes produced, we can expect 400/16 = 25 seeds with genotype TtRr.
Therefore, the correct answer is not listed in the options provided.
To determine the number of seeds with genotype TtRr produced by the dihybrid plant, we need to consider the principles of Mendelian genetics and the results of the self-pollination.
Genotypes and Phenotypes
The dihybrid plant produced 400 phenotypes with 9 genotypes. This means that there are 9 different combinations of alleles present in the offspring. One of these genotypes is TtRr, which represents a plant heterozygous for both traits.
Dihybrid Cross
In a dihybrid cross, the alleles for each trait segregate independently during gamete formation. This means that the gametes produced by the plant will have all possible combinations of alleles for the two traits.
Punnett Square
By using a Punnett square, we can determine the probability of producing a seed with genotype TtRr. In this case, the probability is 1/16, as there are 16 possible combinations of alleles in the square and only one of them is TtRr.
Calculation
Since the probability of producing a seed with genotype TtRr is 1/16, out of the 400 phenotypes produced, we can expect 400/16 = 25 seeds with genotype TtRr.
Therefore, the correct answer is not listed in the options provided.
Community Answer
a dihybrid plant on self pollination , produced 400 phenotypes with 9 ...
200
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a dihybrid plant on self pollination , produced 400 phenotypes with 9 genotypes . How many seeds will have genotype TtRr 1) 200 2) 100 3)50. 4)150
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a dihybrid plant on self pollination , produced 400 phenotypes with 9 genotypes . How many seeds will have genotype TtRr 1) 200 2) 100 3)50. 4)150 for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about a dihybrid plant on self pollination , produced 400 phenotypes with 9 genotypes . How many seeds will have genotype TtRr 1) 200 2) 100 3)50. 4)150 covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for a dihybrid plant on self pollination , produced 400 phenotypes with 9 genotypes . How many seeds will have genotype TtRr 1) 200 2) 100 3)50. 4)150.
a dihybrid plant on self pollination , produced 400 phenotypes with 9 genotypes . How many seeds will have genotype TtRr 1) 200 2) 100 3)50. 4)150 for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about a dihybrid plant on self pollination , produced 400 phenotypes with 9 genotypes . How many seeds will have genotype TtRr 1) 200 2) 100 3)50. 4)150 covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for a dihybrid plant on self pollination , produced 400 phenotypes with 9 genotypes . How many seeds will have genotype TtRr 1) 200 2) 100 3)50. 4)150.
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