the volume of 2 grams of O2 at NTP is 1) 2.4 litres2) 4.8 litres 3) 1....
The volume of 2 grams of O2 at NTP
Calculation
To solve this problem, we need to use the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature. At NTP, the pressure is 1 atm, the temperature is 273 K, and the molar volume of any ideal gas is 22.4 L/mol. We can use this information to calculate the volume of 2 grams of O2 at NTP.
- Convert mass to moles: 2 g O2 / (32 g/mol) = 0.0625 mol O2
- Calculate volume: V = nRT/P = (0.0625 mol)(0.0821 L·atm/mol·K)(273 K) / (1 atm) = 1.21 L
Answer
Therefore, the volume of 2 grams of O2 at NTP is 1.2 litres (option 4).
Explanation
The calculation is straight forward using the ideal gas law. It is important to note that the molar volume of any ideal gas at STP or NTP is 22.4 L/mol. This is derived from the definition of STP and NTP. The mass to mole conversion is also a simple stoichiometric calculation where we divide the given mass by the molar mass of O2. It is important to note that we are assuming that the O2 gas behaves ideally under the given conditions. This is not always the case in reality, but for most purposes, ideal gas law calculations are sufficient.
the volume of 2 grams of O2 at NTP is 1) 2.4 litres2) 4.8 litres 3) 1....
32g O2 22.4L so 2g O2 1.4L
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.