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The number of densities of electrons and holes in pure silicon at 27°C are equal and its value is 1.5 x 1016m-3. On doping with indium, the hole density increases to 4.5 x 1027m-3. The electron density in doped silicon will be
  • a)
    50 x 10m-3
  • b)
    5 x 109 m-3
  • c)
    10m-3
  • d)
    10m-3
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The number of densities of electrons and holes in pure silicon at 27&d...
nc2 = ncnn
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The number of densities of electrons and holes in pure silicon at 27°C are equal and its value is 1.5 x 1016m-3. On doping with indium, the hole density increases to 4.5 x 1027m-3. The electron density in doped silicon will bea)50 x 109m-3b)5 x 109 m-3c)108m-3d)107m-3Correct answer is option 'B'. Can you explain this answer?
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The number of densities of electrons and holes in pure silicon at 27°C are equal and its value is 1.5 x 1016m-3. On doping with indium, the hole density increases to 4.5 x 1027m-3. The electron density in doped silicon will bea)50 x 109m-3b)5 x 109 m-3c)108m-3d)107m-3Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The number of densities of electrons and holes in pure silicon at 27°C are equal and its value is 1.5 x 1016m-3. On doping with indium, the hole density increases to 4.5 x 1027m-3. The electron density in doped silicon will bea)50 x 109m-3b)5 x 109 m-3c)108m-3d)107m-3Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The number of densities of electrons and holes in pure silicon at 27°C are equal and its value is 1.5 x 1016m-3. On doping with indium, the hole density increases to 4.5 x 1027m-3. The electron density in doped silicon will bea)50 x 109m-3b)5 x 109 m-3c)108m-3d)107m-3Correct answer is option 'B'. Can you explain this answer?.
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