How much copper we can obtain from 100g of copper sulphate(CuSO4)?

Question

Answer

Answer

1 mole of copper sulphate contains 1 mole of Cu

Molar mass of CuSO4 =159.5 g

159.5 g of CuSO4 contains 63.5 g of Cu

Therefore, the amount of Cu that can be obtained from 100g of CuSO4:

=159.563.5×100

=39.81 g

Answer

Molar mass of ( CuSO4 ) = 63.5 + 32 + 64 = 159.5 g 159.5g of CuSO4 contains copper = 63.5 g 1 g of CuSO4 contains copper = 63.5 / 159.5 100 g of CuSO4 contains copper = 63.5 / 159 . 5 × 100 = 39 . 81g So , we can obtain 39 . 81 g of copper from 100 g of (CuSO4) .

Answer

Introduction
Copper sulphate (CuSO4) is a salt that contains copper, sulfur, and oxygen. Copper is a highly conductive metal that is widely used in electrical wiring, plumbing, and electronics. Copper sulphate is commonly used in agriculture as a fungicide and as a source of copper for animal feed.

Calculating the amount of copper in 100g of copper sulphate
To calculate the amount of copper in 100g of copper sulphate, we need to first determine the molar mass of copper sulphate. The molar mass of CuSO4 is 159.61 g/mol. This means that 1 mole of CuSO4 contains 1 mole of copper (Cu).

Next, we need to convert the mass of CuSO4 to moles of CuSO4. To do this, we divide the given mass by the molar mass of CuSO4:

100g CuSO4 / 159.61 g/mol = 0.626 moles CuSO4

Since 1 mole of CuSO4 contains 1 mole of Cu, we can say that there are 0.626 moles of Cu in 100g of CuSO4.

Finally, we can convert the moles of Cu to grams of Cu by multiplying by the molar mass of Cu:

0.626 moles Cu x 63.55 g/mol = 39.8 g Cu

Therefore, we can obtain approximately 39.8 grams of copper from 100g of copper sulphate.

Conclusion
In summary, we can obtain approximately 39.8 grams of copper from 100g of copper sulphate. This calculation is based on the molar mass of copper sulphate and the fact that 1 mole of CuSO4 contains 1 mole of copper.

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