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A uniform ladder of mass 10kg links against smooth vertical wall making an angle 53 degree C with it. The other end is rested on rough horizontal floor. Find the normal force & frictional force that floor exert on the ladder.?
Most Upvoted Answer
A uniform ladder of mass 10kg links against smooth vertical wall makin...
There are four forces acting on the ladder of length L and making ?=53

degrees with the vertical smooth wall and on a horizontal rough floor.

1. the weight W=(10×9.8) = 98 N

acting downwards through the middle of the ladder

2. vertical reaction on the floor acting upwards, equal to W.

These two forces form a couple of magnitude

W(2L​)sin?

3. Normal reaction N on the wall (horizontal) at the top end of the ladder,

equal in magnitude to

4. Frictional force F acting horizontally at the bottom of the ladder.

These two forces form another couple equal to FLcos?.

Since the ladder is in equilibrium, the two couples must be equal, thus

W(2L​)sin? = FLcos?

From which we can solve for F

= (2W​)tan?

= (298​) tan 530

= 65 N
Community Answer
A uniform ladder of mass 10kg links against smooth vertical wall makin...
To find the normal force, we need to consider the forces acting on the ladder.

The forces acting on the ladder are:
1. Weight (mg) acting downward at the center of mass of the ladder
2. Normal force (N) acting upward at the point of contact between the ladder and the floor
3. Frictional force (f) acting horizontally in the opposite direction of motion at the point of contact between the ladder and the floor
4. Reaction force (R) acting perpendicular to the wall at the point of contact between the ladder and the wall

Since the ladder is in equilibrium, the sum of the vertical forces and the sum of the horizontal forces must be equal to zero.

Vertical forces:
Sum of the vertical forces = N - mg = 0
N = mg

Horizontal forces:
Sum of the horizontal forces = f = 0
f = 0 because the ladder is resting on a rough horizontal floor and is not moving horizontally.

To find the normal force, we need to find the weight (mg) of the ladder. Since the ladder has a mass of 10 kg, and the acceleration due to gravity is approximately 9.8 m/s^2, the weight of the ladder is:
Weight (mg) = 10 kg * 9.8 m/s^2 = 98 N

Therefore, the normal force is equal to the weight of the ladder, which is 98 N.
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A uniform ladder of mass 10kg links against smooth vertical wall making an angle 53 degree C with it. The other end is rested on rough horizontal floor. Find the normal force & frictional force that floor exert on the ladder.?
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A uniform ladder of mass 10kg links against smooth vertical wall making an angle 53 degree C with it. The other end is rested on rough horizontal floor. Find the normal force & frictional force that floor exert on the ladder.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A uniform ladder of mass 10kg links against smooth vertical wall making an angle 53 degree C with it. The other end is rested on rough horizontal floor. Find the normal force & frictional force that floor exert on the ladder.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A uniform ladder of mass 10kg links against smooth vertical wall making an angle 53 degree C with it. The other end is rested on rough horizontal floor. Find the normal force & frictional force that floor exert on the ladder.?.
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