the reaction A+ B gives C+D is studies in one litre vessel at 250C the...
see A+B gives C+D so u write the reactn so initially...3n moles of A and n moles of B and 0 moles of C and D are present since volume is 1L so 3n and n can B counted as moles...bcz n/v=n/1...so at equilibrium...let's assume x moles of C and x moles of D are formed ...therefore at equilibrium no. of moles of A will be 3n-x and that of B will be n-x...since it is given that conc of B and C is equal ....so n-x=xn=2xtherfr x=n/2....i.e. conc of D which is equal to x is n/2... the mistake I did was taking conc of A and B as 3n-2x and n-2x respectively...if u do so u will get n/3 as the ans which is wrong...so u have to take it as 3n-x and n-x bcz 3n-2x means one reactant alone gives the 2 products which is wrong...hope u got it 😊
the reaction A+ B gives C+D is studies in one litre vessel at 250C the...
Reaction A + B → C + D
Initial concentrations:
[A] = 3n
[B] = n
Equilibrium concentration of C = equilibrium concentration of B
Let's assume the equilibrium concentrations of C and D are both x.
At equilibrium, the reaction reaches a state where the rate of the forward reaction (A + B → C + D) is equal to the rate of the backward reaction (C + D → A + B). This indicates that the concentrations of all the species involved in the reaction remain constant over time.
To determine the equilibrium concentration of D, we need to analyze the stoichiometry of the reaction. From the balanced equation, we can see that for every one mole of C produced, one mole of D is also produced.
Therefore, the moles of C and D produced at equilibrium are equal. Since the initial concentration of B is n, and the equilibrium concentration of C is x (which is also equal to the equilibrium concentration of B), the equilibrium concentration of D is also x.
In terms of concentrations:
[C] = [B] = x
[D] = x
Thus, the concentration of D at equilibrium is x, which is also equal to the equilibrium concentration of C.
To summarize:
- The equilibrium concentration of C is equal to the equilibrium concentration of B, both denoted as x.
- The concentration of D at equilibrium is also x, as the stoichiometry of the reaction dictates that the moles of C and D produced are equal.
Overall, the equilibrium concentrations of C and D are equal, denoted as x, while the concentrations of A and B depend on their initial concentrations and the extent of the reaction.
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