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At t = 0, light of intensity 1012 photons/s–m2 of energy 6eV per photon start falling on a plate with work function 2.5 eV. If area of the plate is 2 × 10-4 m2 and for every 105 photons one photoelectron is emitted, charge on the plate at t = 25 s isa)8 × 10-14 Cb)4 × 10-14 Cc)12 × 10-14 Cd)16 × 10-14 CCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about At t = 0, light of intensity 1012 photons/s–m2 of energy 6eV per photon start falling on a plate with work function 2.5 eV. If area of the plate is 2 × 10-4 m2 and for every 105 photons one photoelectron is emitted, charge on the plate at t = 25 s isa)8 × 10-14 Cb)4 × 10-14 Cc)12 × 10-14 Cd)16 × 10-14 CCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At t = 0, light of intensity 1012 photons/s–m2 of energy 6eV per photon start falling on a plate with work function 2.5 eV. If area of the plate is 2 × 10-4 m2 and for every 105 photons one photoelectron is emitted, charge on the plate at t = 25 s isa)8 × 10-14 Cb)4 × 10-14 Cc)12 × 10-14 Cd)16 × 10-14 CCorrect answer is option 'A'. Can you explain this answer?.

Solutions for At t = 0, light of intensity 1012 photons/s–m2 of energy 6eV per photon start falling on a plate with work function 2.5 eV. If area of the plate is 2 × 10-4 m2 and for every 105 photons one photoelectron is emitted, charge on the plate at t = 25 s isa)8 × 10-14 Cb)4 × 10-14 Cc)12 × 10-14 Cd)16 × 10-14 CCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

Here you can find the meaning of At t = 0, light of intensity 1012 photons/s–m2 of energy 6eV per photon start falling on a plate with work function 2.5 eV. If area of the plate is 2 × 10-4 m2 and for every 105 photons one photoelectron is emitted, charge on the plate at t = 25 s isa)8 × 10-14 Cb)4 × 10-14 Cc)12 × 10-14 Cd)16 × 10-14 CCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of At t = 0, light of intensity 1012 photons/s–m2 of energy 6eV per photon start falling on a plate with work function 2.5 eV. If area of the plate is 2 × 10-4 m2 and for every 105 photons one photoelectron is emitted, charge on the plate at t = 25 s isa)8 × 10-14 Cb)4 × 10-14 Cc)12 × 10-14 Cd)16 × 10-14 CCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for At t = 0, light of intensity 1012 photons/s–m2 of energy 6eV per photon start falling on a plate with work function 2.5 eV. If area of the plate is 2 × 10-4 m2 and for every 105 photons one photoelectron is emitted, charge on the plate at t = 25 s isa)8 × 10-14 Cb)4 × 10-14 Cc)12 × 10-14 Cd)16 × 10-14 CCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of At t = 0, light of intensity 1012 photons/s–m2 of energy 6eV per photon start falling on a plate with work function 2.5 eV. If area of the plate is 2 × 10-4 m2 and for every 105 photons one photoelectron is emitted, charge on the plate at t = 25 s isa)8 × 10-14 Cb)4 × 10-14 Cc)12 × 10-14 Cd)16 × 10-14 CCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice At t = 0, light of intensity 1012 photons/s–m2 of energy 6eV per photon start falling on a plate with work function 2.5 eV. If area of the plate is 2 × 10-4 m2 and for every 105 photons one photoelectron is emitted, charge on the plate at t = 25 s isa)8 × 10-14 Cb)4 × 10-14 Cc)12 × 10-14 Cd)16 × 10-14 CCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice NEET tests.