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A dielectric slab is inserted between the plates of an isolated charged capacitor. Which of the following quantities will remain the same?
- a)the electric field in the capacitor
- b)the charge on the capacitor
- c)the potential difference between the plates
- d)the stored energy in the capacitor
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A dielectric slab is inserted between the plates of anisolated charged...
Explanation:
When a dielectric slab is inserted between the plates of an isolated charged capacitor, the following changes occur:
1. Electric Field: The electric field decreases by a factor of the dielectric constant of the material. This is because the dielectric material reduces the electric field by polarizing the material and creating an opposing electric field.
2. Charge: The charge on the capacitor remains the same. This is because the charge on the capacitor is determined by the potential difference between the plates and the capacitance of the capacitor. As the potential difference remains the same and the capacitance increases, the charge on the capacitor remains constant.
3. Potential Difference: The potential difference between the plates decreases by a factor of the dielectric constant of the material. This is because the dielectric material reduces the electric field, which in turn reduces the potential difference between the plates.
4. Stored Energy: The stored energy in the capacitor increases by a factor of the dielectric constant of the material. This is because the capacitance of the capacitor increases due to the insertion of the dielectric material, and the energy stored in a capacitor is proportional to the square of the capacitance.
Therefore, the only quantity that remains the same is the charge on the capacitor.
When a dielectric slab is inserted between the plates of an isolated charged capacitor, the following changes occur:
1. Electric Field: The electric field decreases by a factor of the dielectric constant of the material. This is because the dielectric material reduces the electric field by polarizing the material and creating an opposing electric field.
2. Charge: The charge on the capacitor remains the same. This is because the charge on the capacitor is determined by the potential difference between the plates and the capacitance of the capacitor. As the potential difference remains the same and the capacitance increases, the charge on the capacitor remains constant.
3. Potential Difference: The potential difference between the plates decreases by a factor of the dielectric constant of the material. This is because the dielectric material reduces the electric field, which in turn reduces the potential difference between the plates.
4. Stored Energy: The stored energy in the capacitor increases by a factor of the dielectric constant of the material. This is because the capacitance of the capacitor increases due to the insertion of the dielectric material, and the energy stored in a capacitor is proportional to the square of the capacitance.
Therefore, the only quantity that remains the same is the charge on the capacitor.
Community Answer
A dielectric slab is inserted between the plates of anisolated charged...
Since the capacitor is isolated the charge between plates remains constant.
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A dielectric slab is inserted between the plates of anisolated charged capacitor. Which of the following quantitieswill remain the same?a)the electric field in the capacitorb)the charge on the capacitorc)the potential difference between the platesd)the stored energy in the capacitorCorrect answer is option 'B'. Can you explain this answer?
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