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A point source of electromagnetic radiation has an average power output of 1500 W. The maximum value of electric field at a distance of 3m from this sources in Vm–1 is (a) 500 (b) 100 (c) 500 3 (d) 250 3?
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Calculation of Electric Field
To calculate the electric field at a distance of 3m from the electromagnetic radiation source, we need to use the formula:
E = (2P/4πε₀r²)¹/²
Where P is the average power output of the source, r is the distance from the source, and ε₀ is the permittivity of free space.
Substituting the values, we get:
E = (2 x 1500 W / 4π x 8.85 x 10⁻¹² F/m x (3 m)²)¹/²
E = 250 3 V/m
Therefore, the maximum value of electric field at a distance of 3m from the source is 250 3 V/m.
Explanation
The electric field strength decreases as the distance from the source increases. This is because the energy is spread out over a larger area as it travels away from the source. The formula used to calculate the electric field takes into account the power output of the source and the distance from the source. The permittivity of free space is a constant value that relates to the ability of a vacuum to support electric fields.
The answer to this question is (d) 250 3. This is because the calculation shows that the electric field at a distance of 3m from the source is 250 3 V/m. Therefore, this is the maximum value of electric field at that distance.
To calculate the electric field at a distance of 3m from the electromagnetic radiation source, we need to use the formula:
E = (2P/4πε₀r²)¹/²
Where P is the average power output of the source, r is the distance from the source, and ε₀ is the permittivity of free space.
Substituting the values, we get:
E = (2 x 1500 W / 4π x 8.85 x 10⁻¹² F/m x (3 m)²)¹/²
E = 250 3 V/m
Therefore, the maximum value of electric field at a distance of 3m from the source is 250 3 V/m.
Explanation
The electric field strength decreases as the distance from the source increases. This is because the energy is spread out over a larger area as it travels away from the source. The formula used to calculate the electric field takes into account the power output of the source and the distance from the source. The permittivity of free space is a constant value that relates to the ability of a vacuum to support electric fields.
The answer to this question is (d) 250 3. This is because the calculation shows that the electric field at a distance of 3m from the source is 250 3 V/m. Therefore, this is the maximum value of electric field at that distance.
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A point source of electromagnetic radiation has an average power output of 1500 W. The maximum value of electric field at a distance of 3m from this sources in Vm–1 is (a) 500 (b) 100 (c) 500 3 (d) 250 3?
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A point source of electromagnetic radiation has an average power output of 1500 W. The maximum value of electric field at a distance of 3m from this sources in Vm–1 is (a) 500 (b) 100 (c) 500 3 (d) 250 3? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A point source of electromagnetic radiation has an average power output of 1500 W. The maximum value of electric field at a distance of 3m from this sources in Vm–1 is (a) 500 (b) 100 (c) 500 3 (d) 250 3? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A point source of electromagnetic radiation has an average power output of 1500 W. The maximum value of electric field at a distance of 3m from this sources in Vm–1 is (a) 500 (b) 100 (c) 500 3 (d) 250 3?.
A point source of electromagnetic radiation has an average power output of 1500 W. The maximum value of electric field at a distance of 3m from this sources in Vm–1 is (a) 500 (b) 100 (c) 500 3 (d) 250 3? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A point source of electromagnetic radiation has an average power output of 1500 W. The maximum value of electric field at a distance of 3m from this sources in Vm–1 is (a) 500 (b) 100 (c) 500 3 (d) 250 3? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A point source of electromagnetic radiation has an average power output of 1500 W. The maximum value of electric field at a distance of 3m from this sources in Vm–1 is (a) 500 (b) 100 (c) 500 3 (d) 250 3?.
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