A particle of mass 2kg moves ona circular path with constant speed 10m...
Given:Mass of particle, m = 2 kg
Speed of particle, v = 10 m/s
Angle of revolution, θ = 180°
To find:Change in speed
Magnitude of change in velocity
Change in speed:
As the speed of the particle is constant, there will be no change in speed during half revolution.
Therefore, the change in speed = 0 m/s
Magnitude of change in velocity:
The magnitude of change in velocity can be calculated using the formula:
Δv = v * √2 * (1 - cos(θ/2))
Where,
v = speed of particle = 10 m/s
θ = angle of revolution = 180°
On substituting the given values, we get:
Δv = 10 * √2 * (1 - cos(90))
Δv = 10 * √2 * (1 - 0)
Δv = 10 * √2
Therefore, the magnitude of change in velocity = 14.14 m/s
Explanation:
When a particle moves in a circular path with constant speed, its speed remains constant throughout the motion. However, the direction of velocity changes at every point on the circle.
To calculate the change in speed, we need to find the difference between the initial and final speeds of the particle. As the speed is constant, there will be no change in speed during half revolution.
To calculate the magnitude of change in velocity, we can use the formula Δv = v * √2 * (1 - cos(θ/2)). This formula takes into account the change in direction of velocity at every point on the circle. The angle of revolution is given as 180°, which represents half a revolution. On substituting the given values in the formula, we get the magnitude of change in velocity as 14.14 m/s.
Overall, this problem involves using the concepts of circular motion, constant speed, and change in velocity.