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The IUPAC name of the compound
 
  • a)
    Pent – 2 – enoic acid
  • b)
    Pent – 3 – enoic acid
  • c)
    Pent – 2 –en – 4 - enoic acid
  • d)
    Pent – 2 – en- 5 - enoic acid
Correct answer is option 'B'. Can you explain this answer?
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The IUPAC name of the compounda)Pent – 2 – enoic acidb)Pen...
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The IUPAC name of the compounda)Pent – 2 – enoic acidb)Pen...
Option-(B) pent-3-enoic acid.
CH3—CH = CH—CH2—COOH.
5. 4. 3. 2. 1.
first preference is given to carboxylic acid group over double bond.
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The IUPAC name of the compounda)Pent – 2 – enoic acidb)Pent – 3 – enoic acidc)Pent – 2 –en – 4 - enoic acidd)Pent – 2 – en- 5 - enoic acidCorrect answer is option 'B'. Can you explain this answer?
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