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Body of mass M is thrown with velocity V making an angle 45 degree with horizontal. The magnitude of change in momentum between starting point at and maximum height is?
Most Upvoted Answer
Body of mass M is thrown with velocity V making an angle 45 degree wit...
Change in momentum= M (change in velocity).
as initial velocity = v cos theta i^ + vsin theta j^. & velocity at highest point = v cos theta i^. since overall change in velocity = v sin theta j^ = v sin 45= v / sqrt.2. & change in momentum = Mv/ sqrt.2. j^
Community Answer
Body of mass M is thrown with velocity V making an angle 45 degree wit...
@maxi height horizontal velocity of the body is zero, so change in momentum along x is zero. whereas along y change in momentum=MV-MVsin45=MV-MV(.707)=.293MV
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Body of mass M is thrown with velocity V making an angle 45 degree with horizontal. The magnitude of change in momentum between starting point at and maximum height is?
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