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What will be the partial pressure of He and O2 respectively, if 200ml of He at 0.66atm and 400ml of O2 at 0.52 atm pressure are mixed in 400 ml vessel at 20 degrees Celsius. A) 0.33 & 0.56 B)0.33 & 0.52 C) 0.38 & 0.52 D) 0.35&0.49?
Most Upvoted Answer
What will be the partial pressure of He and O2 respectively, if 200ml ...
To find the partial pressures of He and O2, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature in Kelvin (20°C = 293.15 K)
First, let's calculate the number of moles for each gas:
For He:
n(He) = (PV)/(RT)
= (0.66 atm * 0.2 L) / (0.0821 L·atm/(mol·K) * 293.15 K)
≈ 0.0057 mol
For O2:
n(O2) = (PV)/(RT)
= (0.52 atm * 0.4 L) / (0.0821 L·atm/(mol·K) * 293.15 K)
≈ 0.027 mol
Next, let's find the total number of moles of gas in the mixture:
n(total) = n(He) + n(O2)
= 0.0057 mol + 0.027 mol
≈ 0.0327 mol
Finally, we can find the partial pressures of He and O2:
P(He) = (n(He) * RT) / V
= (0.0057 mol * 0.0821 L·atm/(mol·K) * 293.15 K) / 0.4 L
≈ 0.331 atm
P(O2) = (n(O2) * RT) / V
= (0.027 mol * 0.0821 L·atm/(mol·K) * 293.15 K) / 0.4 L
≈ 1.422 atm
Therefore, the partial pressure of He is approximately 0.331 atm and the partial pressure of O2 is approximately 1.422 atm.
PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature in Kelvin (20°C = 293.15 K)
First, let's calculate the number of moles for each gas:
For He:
n(He) = (PV)/(RT)
= (0.66 atm * 0.2 L) / (0.0821 L·atm/(mol·K) * 293.15 K)
≈ 0.0057 mol
For O2:
n(O2) = (PV)/(RT)
= (0.52 atm * 0.4 L) / (0.0821 L·atm/(mol·K) * 293.15 K)
≈ 0.027 mol
Next, let's find the total number of moles of gas in the mixture:
n(total) = n(He) + n(O2)
= 0.0057 mol + 0.027 mol
≈ 0.0327 mol
Finally, we can find the partial pressures of He and O2:
P(He) = (n(He) * RT) / V
= (0.0057 mol * 0.0821 L·atm/(mol·K) * 293.15 K) / 0.4 L
≈ 0.331 atm
P(O2) = (n(O2) * RT) / V
= (0.027 mol * 0.0821 L·atm/(mol·K) * 293.15 K) / 0.4 L
≈ 1.422 atm
Therefore, the partial pressure of He is approximately 0.331 atm and the partial pressure of O2 is approximately 1.422 atm.
Community Answer
What will be the partial pressure of He and O2 respectively, if 200ml ...
P1×v1=p2×v2
ans::B
ans::B
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What will be the partial pressure of He and O2 respectively, if 200ml of He at 0.66atm and 400ml of O2 at 0.52 atm pressure are mixed in 400 ml vessel at 20 degrees Celsius. A) 0.33 & 0.56 B)0.33 & 0.52 C) 0.38 & 0.52 D) 0.35&0.49?
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What will be the partial pressure of He and O2 respectively, if 200ml of He at 0.66atm and 400ml of O2 at 0.52 atm pressure are mixed in 400 ml vessel at 20 degrees Celsius. A) 0.33 & 0.56 B)0.33 & 0.52 C) 0.38 & 0.52 D) 0.35&0.49? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about What will be the partial pressure of He and O2 respectively, if 200ml of He at 0.66atm and 400ml of O2 at 0.52 atm pressure are mixed in 400 ml vessel at 20 degrees Celsius. A) 0.33 & 0.56 B)0.33 & 0.52 C) 0.38 & 0.52 D) 0.35&0.49? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What will be the partial pressure of He and O2 respectively, if 200ml of He at 0.66atm and 400ml of O2 at 0.52 atm pressure are mixed in 400 ml vessel at 20 degrees Celsius. A) 0.33 & 0.56 B)0.33 & 0.52 C) 0.38 & 0.52 D) 0.35&0.49?.
What will be the partial pressure of He and O2 respectively, if 200ml of He at 0.66atm and 400ml of O2 at 0.52 atm pressure are mixed in 400 ml vessel at 20 degrees Celsius. A) 0.33 & 0.56 B)0.33 & 0.52 C) 0.38 & 0.52 D) 0.35&0.49? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about What will be the partial pressure of He and O2 respectively, if 200ml of He at 0.66atm and 400ml of O2 at 0.52 atm pressure are mixed in 400 ml vessel at 20 degrees Celsius. A) 0.33 & 0.56 B)0.33 & 0.52 C) 0.38 & 0.52 D) 0.35&0.49? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What will be the partial pressure of He and O2 respectively, if 200ml of He at 0.66atm and 400ml of O2 at 0.52 atm pressure are mixed in 400 ml vessel at 20 degrees Celsius. A) 0.33 & 0.56 B)0.33 & 0.52 C) 0.38 & 0.52 D) 0.35&0.49?.
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