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A 3 microFaraday capacitor is charged to a potential of 300 volt and a 2 micro Faraday is charged to 200 volt .The capacitor are then connected in parallel with plates of opposite polarity joined together what amount of charge will flow when the plates are so connected?
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A 3 microFaraday capacitor is charged to a potential of 300 volt and a...
Solution:

Initial Charge on Capacitors

Initial charge on the 3 microFaraday capacitor with potential difference V1=300V is given by,

Q1 = C1 * V1 = 3 x 10^-6 F x 300 V = 0.9 mC

Initial charge on the 2 microFaraday capacitor with potential difference V2=200V is given by,

Q2 = C2 * V2 = 2 x 10^-6 F x 200 V = 0.4 mC

Total Charge on Capacitors

Total charge on the capacitors before they are connected in parallel is,

Qt = Q1 + Q2 = 0.9 mC + 0.4 mC = 1.3 mC

Charge Flow when Capacitors are Connected in Parallel

When the capacitors are connected in parallel, the plates of opposite polarity are joined together. The potential difference across the combination of capacitors will be the same as the potential difference across each capacitor, which is the same as the initial potential difference.

The equivalent capacitance of the combination of capacitors connected in parallel is,

Ceq = C1 + C2 = 3 x 10^-6 F + 2 x 10^-6 F = 5 x 10^-6 F

The charge on the combination of capacitors is given by,

Q = Ceq * V = 5 x 10^-6 F x 300 V = 1.5 mC

The charge flow when the plates are connected is the difference between the total initial charge on the capacitors and the charge on the combination of capacitors,

Qf = Q - Qt = 1.5 mC - 1.3 mC = 0.2 mC

Therefore, the amount of charge that flows when the plates of the capacitors are connected is 0.2 mC.
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A 3 microFaraday capacitor is charged to a potential of 300 volt and a 2 micro Faraday is charged to 200 volt .The capacitor are then connected in parallel with plates of opposite polarity joined together what amount of charge will flow when the plates are so connected?
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