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A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?
- a)1 hr 15 min
- b)2 hr
- c)4 hr
- d)2 hr 30 min
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A boatman goes 2 km against the current of the stream in 1 hour and go...
Rate downstream = 
Rate upstream = 2 km/hr.
Speed in still water = 
Required time = 
Most Upvoted Answer
A boatman goes 2 km against the current of the stream in 1 hour and go...
Given:
- The boatman goes 2 km against the current in 1 hour.
- The boatman goes 1 km along the current in 10 minutes.
To Find:
- How long will it take to go 5 km in stationary water?
Explanation:
To solve this problem, we need to find the speed of the boatman in stationary water and then use that speed to calculate the time taken to cover a distance of 5 km.
Finding the Speed:
Let's assume the speed of the boatman in stationary water is 'x' km/hr.
- Against the current, the effective speed of the boatman is (x - c) km/hr, where 'c' is the speed of the current.
- Along the current, the effective speed of the boatman is (x + c) km/hr.
Given that the boatman goes 2 km against the current in 1 hour and goes 1 km along the current in 10 minutes, we can form the following equations:
- (x - c) = 2 (Equation 1)
- (x + c) = 6 (Equation 2) [10 minutes is 1/6th of an hour]
Solving these equations, we get:
x = 4 km/hr (speed of boatman in stationary water)
c = 2 km/hr (speed of the current)
Calculating the Time:
Now that we know the speed of the boatman in stationary water, we can calculate the time taken to cover a distance of 5 km.
Let 't' be the time taken to cover 5 km.
- Against the current, the boatman's speed is (4 - 2) = 2 km/hr.
- Along the current, the boatman's speed is (4 + 2) = 6 km/hr.
Using the formula: Speed = Distance/Time, we have:
- Against the current: 2 = 5/t
- Along the current: 6 = 5/t
Simplifying these equations, we get:
- t = 5/2 hours to go against the current
- t = 5/6 hours to go along the current
Converting the time to minutes, we have:
- t = 5/2 * 60 = 150 minutes to go against the current
- t = 5/6 * 60 = 50 minutes to go along the current
The total time taken to cover a distance of 5 km in stationary water is the sum of the time taken against the current and the time taken along the current:
Total time = 150 + 50 = 200 minutes = 3 hours and 20 minutes.
However, none of the options provided match this result. Therefore, it seems that there might be an error in the given answer options or in the calculations.
- The boatman goes 2 km against the current in 1 hour.
- The boatman goes 1 km along the current in 10 minutes.
To Find:
- How long will it take to go 5 km in stationary water?
Explanation:
To solve this problem, we need to find the speed of the boatman in stationary water and then use that speed to calculate the time taken to cover a distance of 5 km.
Finding the Speed:
Let's assume the speed of the boatman in stationary water is 'x' km/hr.
- Against the current, the effective speed of the boatman is (x - c) km/hr, where 'c' is the speed of the current.
- Along the current, the effective speed of the boatman is (x + c) km/hr.
Given that the boatman goes 2 km against the current in 1 hour and goes 1 km along the current in 10 minutes, we can form the following equations:
- (x - c) = 2 (Equation 1)
- (x + c) = 6 (Equation 2) [10 minutes is 1/6th of an hour]
Solving these equations, we get:
x = 4 km/hr (speed of boatman in stationary water)
c = 2 km/hr (speed of the current)
Calculating the Time:
Now that we know the speed of the boatman in stationary water, we can calculate the time taken to cover a distance of 5 km.
Let 't' be the time taken to cover 5 km.
- Against the current, the boatman's speed is (4 - 2) = 2 km/hr.
- Along the current, the boatman's speed is (4 + 2) = 6 km/hr.
Using the formula: Speed = Distance/Time, we have:
- Against the current: 2 = 5/t
- Along the current: 6 = 5/t
Simplifying these equations, we get:
- t = 5/2 hours to go against the current
- t = 5/6 hours to go along the current
Converting the time to minutes, we have:
- t = 5/2 * 60 = 150 minutes to go against the current
- t = 5/6 * 60 = 50 minutes to go along the current
The total time taken to cover a distance of 5 km in stationary water is the sum of the time taken against the current and the time taken along the current:
Total time = 150 + 50 = 200 minutes = 3 hours and 20 minutes.
However, none of the options provided match this result. Therefore, it seems that there might be an error in the given answer options or in the calculations.
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A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?a)1 hr 15 minb)2 hrc)4 hrd)2 hr 30 minCorrect answer is option 'A'. Can you explain this answer? for LR 2025 is part of LR preparation. The Question and answers have been prepared according to the LR exam syllabus. Information about A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?a)1 hr 15 minb)2 hrc)4 hrd)2 hr 30 minCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for LR 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?a)1 hr 15 minb)2 hrc)4 hrd)2 hr 30 minCorrect answer is option 'A'. Can you explain this answer?.
A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?a)1 hr 15 minb)2 hrc)4 hrd)2 hr 30 minCorrect answer is option 'A'. Can you explain this answer? for LR 2025 is part of LR preparation. The Question and answers have been prepared according to the LR exam syllabus. Information about A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?a)1 hr 15 minb)2 hrc)4 hrd)2 hr 30 minCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for LR 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?a)1 hr 15 minb)2 hrc)4 hrd)2 hr 30 minCorrect answer is option 'A'. Can you explain this answer?.
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A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?a)1 hr 15 minb)2 hrc)4 hrd)2 hr 30 minCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?a)1 hr 15 minb)2 hrc)4 hrd)2 hr 30 minCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?a)1 hr 15 minb)2 hrc)4 hrd)2 hr 30 minCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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