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Half of the space between a parallel plate capacitor is filled with a medium of dielectric constant K parallel to the plate . If initially the capacity was C , then the new capacity will be?
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Half of the space between a parallel plate capacitor is filled with a ...
Explanation:
Given parameters:
Initial capacity of the parallel plate capacitor = C
Dielectric constant of the medium = K
Half of the space between the plates is filled with the dielectric material. Therefore, the distance between the plates, d is reduced to d/2.
The electric field intensity between the plates, E = V/d, where V is the potential difference between the plates.
The potential difference between the plates remains the same before and after the introduction of the dielectric material.
Therefore, the electric field intensity between the plates after the introduction of the dielectric material is reduced to E/K.
The capacitance, C’ of the parallel plate capacitor with the dielectric material is given by the formula:
C’ = E0 x K x A/(d/2)
where E0 is the permittivity of free space, A is the area of the plates, and d/2 is the distance between the plates with the dielectric material.
Substituting the values, we get:
C’ = 2 x C
Therefore, the new capacity of the parallel plate capacitor is twice the initial capacity.
Final Answer:
The new capacity of the parallel plate capacitor is 2C.
Given parameters:
Initial capacity of the parallel plate capacitor = C
Dielectric constant of the medium = K
Half of the space between the plates is filled with the dielectric material. Therefore, the distance between the plates, d is reduced to d/2.
The electric field intensity between the plates, E = V/d, where V is the potential difference between the plates.
The potential difference between the plates remains the same before and after the introduction of the dielectric material.
Therefore, the electric field intensity between the plates after the introduction of the dielectric material is reduced to E/K.
The capacitance, C’ of the parallel plate capacitor with the dielectric material is given by the formula:
C’ = E0 x K x A/(d/2)
where E0 is the permittivity of free space, A is the area of the plates, and d/2 is the distance between the plates with the dielectric material.
Substituting the values, we get:
C’ = 2 x C
Therefore, the new capacity of the parallel plate capacitor is twice the initial capacity.
Final Answer:
The new capacity of the parallel plate capacitor is 2C.
Community Answer
Half of the space between a parallel plate capacitor is filled with a ...
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Half of the space between a parallel plate capacitor is filled with a medium of dielectric constant K parallel to the plate . If initially the capacity was C , then the new capacity will be?
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Half of the space between a parallel plate capacitor is filled with a medium of dielectric constant K parallel to the plate . If initially the capacity was C , then the new capacity will be? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Half of the space between a parallel plate capacitor is filled with a medium of dielectric constant K parallel to the plate . If initially the capacity was C , then the new capacity will be? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Half of the space between a parallel plate capacitor is filled with a medium of dielectric constant K parallel to the plate . If initially the capacity was C , then the new capacity will be?.
Half of the space between a parallel plate capacitor is filled with a medium of dielectric constant K parallel to the plate . If initially the capacity was C , then the new capacity will be? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Half of the space between a parallel plate capacitor is filled with a medium of dielectric constant K parallel to the plate . If initially the capacity was C , then the new capacity will be? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Half of the space between a parallel plate capacitor is filled with a medium of dielectric constant K parallel to the plate . If initially the capacity was C , then the new capacity will be?.
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