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Directions: Read the following information and answer the questions that follow.
There are 4 persons A, B, C and D.
i) The total amount of money with A and B together is equal to the total amount of money with C and D together.
ii) The amount of money with B and D together is more than the amount of money with A and C together.
iii) The amount of money with A is twice than that of B.
iv) B has Rs 10 with him.
Q. Which of the following persons has the second highest amount of money?
  • a)
    C
  • b)
    B
  • c)
    A
  • d)
    D
Correct answer is option 'C'. Can you explain this answer?
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Directions:Read the following information and answer the questions tha...
From the above conditions we get the equations as follows,
i) A + B = C + D
ii) B + D > A + C
iii) A = 2B
iv) B = 10
Now we use the condition iii) i.e., A = 2B for further solving
Let us assume A as 20 and B as 10.
A = 2B
A = 2 × 10 = 20
Let us place the values of A and B in the 1st equation,
i) A + B = C + D
20 + 10 = C + D
30 = C + D
C = 30 – D
Now let us place the values of A and B in the 2nd equation, we get
ii) B + D > A + C
10 + D > 20 + C
D > 10 + C [i.e., D > C]
We know that [C = 30 – D], so replace the value of C in the equation [D > 10 + C]
D > 10 + C
D > 10 + 30 – D
2D > 40
D > 20
After solving, we find out that D consists of a value more than 20.
We already know that A = 20 and B = 10.
So, D > A > B and D > C
Therefore, we finally get the condition as D > A > B > C.
Hence, A has the second highest amount of money.
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Most Upvoted Answer
Directions:Read the following information and answer the questions tha...
From the above conditions we get the equations as follows,
i) A + B = C + D
ii) B + D > A + C
iii) A = 2B
iv) B = 10
Now we use the condition iii) i.e., A = 2B for further solving
Let us assume A as 20 and B as 10.
A = 2B
A = 2 × 10 = 20
Let us place the values of A and B in the 1st equation,
i) A + B = C + D
20 + 10 = C + D
30 = C + D
C = 30 – D
Now let us place the values of A and B in the 2nd equation, we get
ii) B + D > A + C
10 + D > 20 + C
D > 10 + C [i.e., D > C]
We know that [C = 30 – D], so replace the value of C in the equation [D > 10 + C]
D > 10 + C
D > 10 + 30 – D
2D > 40
D > 20
After solving, we find out that D consists of a value more than 20.
We already know that A = 20 and B = 10.
So, D > A > B and D > C
Therefore, we finally get the condition as D > A > B > C.
Hence, A has the second highest amount of money.
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