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A bullet moving horizontally with speed "u", strikes a vertically suspended Bob of same Maas and emerges with 80percentage of initial speed. The maximum height attained by Bob is 20metre, then "u" is equal to( assume there is no loss of Maas)?
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A bullet moving horizontally with speed "u", strikes a vertically susp...
Given:
- A bullet of mass m moving horizontally with speed u strikes a vertically suspended bob of the same mass.
- The bullet emerges with 80% of its initial speed.
To find:
The initial speed u of the bullet.
Assumptions:
- There is no loss of mass during the collision.
- The bullet and bob are the only objects involved in the collision.
Analysis:
When the bullet strikes the bob, it transfers some of its momentum to the bob. The bullet emerges with 80% of its initial speed, which means it loses some of its initial momentum. According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision.
Step 1: Momentum before the collision:
The momentum before the collision can be calculated using the equation:
Initial momentum = m * u
Step 2: Momentum after the collision:
The bullet emerges with 80% of its initial speed, so its final speed is 0.8u. The momentum after the collision can be calculated as:
Final momentum = m * 0.8u
Step 3: Conservation of momentum:
According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Therefore, we can equate the initial momentum to the final momentum:
m * u = m * 0.8u
Step 4: Solving for u:
Simplifying the equation, we get:
u = 0.8u
Dividing both sides by u, we get:
1 = 0.8
Step 5: Conclusion:
Since 1 is not equal to 0.8, there is no solution for u. This means that the given scenario is not physically possible. The bullet cannot emerge with 80% of its initial speed after striking the bob.
- A bullet of mass m moving horizontally with speed u strikes a vertically suspended bob of the same mass.
- The bullet emerges with 80% of its initial speed.
To find:
The initial speed u of the bullet.
Assumptions:
- There is no loss of mass during the collision.
- The bullet and bob are the only objects involved in the collision.
Analysis:
When the bullet strikes the bob, it transfers some of its momentum to the bob. The bullet emerges with 80% of its initial speed, which means it loses some of its initial momentum. According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision.
Step 1: Momentum before the collision:
The momentum before the collision can be calculated using the equation:
Initial momentum = m * u
Step 2: Momentum after the collision:
The bullet emerges with 80% of its initial speed, so its final speed is 0.8u. The momentum after the collision can be calculated as:
Final momentum = m * 0.8u
Step 3: Conservation of momentum:
According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Therefore, we can equate the initial momentum to the final momentum:
m * u = m * 0.8u
Step 4: Solving for u:
Simplifying the equation, we get:
u = 0.8u
Dividing both sides by u, we get:
1 = 0.8
Step 5: Conclusion:
Since 1 is not equal to 0.8, there is no solution for u. This means that the given scenario is not physically possible. The bullet cannot emerge with 80% of its initial speed after striking the bob.
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A bullet moving horizontally with speed "u", strikes a vertically susp...
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A bullet moving horizontally with speed "u", strikes a vertically suspended Bob of same Maas and emerges with 80percentage of initial speed. The maximum height attained by Bob is 20metre, then "u" is equal to( assume there is no loss of Maas)?
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A bullet moving horizontally with speed "u", strikes a vertically suspended Bob of same Maas and emerges with 80percentage of initial speed. The maximum height attained by Bob is 20metre, then "u" is equal to( assume there is no loss of Maas)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A bullet moving horizontally with speed "u", strikes a vertically suspended Bob of same Maas and emerges with 80percentage of initial speed. The maximum height attained by Bob is 20metre, then "u" is equal to( assume there is no loss of Maas)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bullet moving horizontally with speed "u", strikes a vertically suspended Bob of same Maas and emerges with 80percentage of initial speed. The maximum height attained by Bob is 20metre, then "u" is equal to( assume there is no loss of Maas)?.
A bullet moving horizontally with speed "u", strikes a vertically suspended Bob of same Maas and emerges with 80percentage of initial speed. The maximum height attained by Bob is 20metre, then "u" is equal to( assume there is no loss of Maas)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A bullet moving horizontally with speed "u", strikes a vertically suspended Bob of same Maas and emerges with 80percentage of initial speed. The maximum height attained by Bob is 20metre, then "u" is equal to( assume there is no loss of Maas)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bullet moving horizontally with speed "u", strikes a vertically suspended Bob of same Maas and emerges with 80percentage of initial speed. The maximum height attained by Bob is 20metre, then "u" is equal to( assume there is no loss of Maas)?.
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