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A stone is dropped from top of a tower 300 m high and at the same time another is projected vertically upward with a velocity of 100ms-¹ . Find when the two stones meet with each other.?
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A stone is dropped from top of a tower 300 m high and at the same time...
Solution:
Given, height of tower, h = 300 m
Initial velocity of projectile, u = 100 ms-¹
Acceleration due to gravity, g = 9.8 ms-²
Let the time taken by both the stones to meet each other be t.
Using kinematic equation, s = ut + (1/2)gt², we can find the time taken by the stone dropped from the top of the tower to reach the ground.
For the stone dropped from the top of the tower,
s = h = 300 m, u = 0, g = 9.8 ms-²
300 = (1/2)×9.8×t²
t² = 300/4.9
t = √(300/4.9)
t = 7.67 s (approx)
Next, we need to find the height reached by the stone projected vertically upward in time t.
Using the kinematic equation, v = u + gt, we can find the final velocity of the stone projected vertically upward in time t.
For the stone projected vertically upward,
u = 100 ms-¹, g = 9.8 ms-², t = 7.67 s
v = u + gt
v = 100 + 9.8×7.67
v = 176.7 ms-¹ (approx)
Now, using the kinematic equation, v² = u² + 2gs, we can find the height reached by the stone projected vertically upward.
For the stone projected vertically upward,
u = 100 ms-¹, g = 9.8 ms-², v = 176.7 ms-¹
v² = u² + 2gs
s = (v² - u²)/2g
s = (176.7² - 100²)/(2×9.8)
s = 1522.61 m (approx)
Therefore, the two stones will meet each other at a height of 1522.61 m above the ground after approximately 7.67 seconds.
Given, height of tower, h = 300 m
Initial velocity of projectile, u = 100 ms-¹
Acceleration due to gravity, g = 9.8 ms-²
Let the time taken by both the stones to meet each other be t.
Using kinematic equation, s = ut + (1/2)gt², we can find the time taken by the stone dropped from the top of the tower to reach the ground.
For the stone dropped from the top of the tower,
s = h = 300 m, u = 0, g = 9.8 ms-²
300 = (1/2)×9.8×t²
t² = 300/4.9
t = √(300/4.9)
t = 7.67 s (approx)
Next, we need to find the height reached by the stone projected vertically upward in time t.
Using the kinematic equation, v = u + gt, we can find the final velocity of the stone projected vertically upward in time t.
For the stone projected vertically upward,
u = 100 ms-¹, g = 9.8 ms-², t = 7.67 s
v = u + gt
v = 100 + 9.8×7.67
v = 176.7 ms-¹ (approx)
Now, using the kinematic equation, v² = u² + 2gs, we can find the height reached by the stone projected vertically upward.
For the stone projected vertically upward,
u = 100 ms-¹, g = 9.8 ms-², v = 176.7 ms-¹
v² = u² + 2gs
s = (v² - u²)/2g
s = (176.7² - 100²)/(2×9.8)
s = 1522.61 m (approx)
Therefore, the two stones will meet each other at a height of 1522.61 m above the ground after approximately 7.67 seconds.
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A stone is dropped from top of a tower 300 m high and at the same time another is projected vertically upward with a velocity of 100ms-¹ . Find when the two stones meet with each other.?
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A stone is dropped from top of a tower 300 m high and at the same time another is projected vertically upward with a velocity of 100ms-¹ . Find when the two stones meet with each other.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A stone is dropped from top of a tower 300 m high and at the same time another is projected vertically upward with a velocity of 100ms-¹ . Find when the two stones meet with each other.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stone is dropped from top of a tower 300 m high and at the same time another is projected vertically upward with a velocity of 100ms-¹ . Find when the two stones meet with each other.?.
A stone is dropped from top of a tower 300 m high and at the same time another is projected vertically upward with a velocity of 100ms-¹ . Find when the two stones meet with each other.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A stone is dropped from top of a tower 300 m high and at the same time another is projected vertically upward with a velocity of 100ms-¹ . Find when the two stones meet with each other.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stone is dropped from top of a tower 300 m high and at the same time another is projected vertically upward with a velocity of 100ms-¹ . Find when the two stones meet with each other.?.
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