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If 3x2 + ax + 4 is perfectly divisible by x – 5, then the value of a is:
  • a)
    -12
  • b)
    -5
  • c)
    -15.8
  • d)
    -15.6
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
If 3x2+ ax + 4 is perfectly divisible by x – 5, then the value o...
3x2 + ax + 4 is perfectly divisible by x – 5,
⇒ 3 × 25 + 5a + 4 = 0
⇒ 5a = -79
∴ a = -15.8
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Most Upvoted Answer
If 3x2+ ax + 4 is perfectly divisible by x – 5, then the value o...
3x2 + ax + 4 is perfectly divisible by x – 5,
⇒ 3 × 25 + 5a + 4 = 0
⇒ 5a = -79
∴ a = -15.8
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Community Answer
If 3x2+ ax + 4 is perfectly divisible by x – 5, then the value o...
Given Information:
3x^2 + ax + 4 is perfectly divisible by x – 5

Explanation:
When a polynomial is perfectly divisible by another polynomial, it means that when the first polynomial is divided by the second, the remainder is zero.

Using the Remainder Theorem:
When 3x^2 + ax + 4 is divided by x – 5, the remainder will be zero.
Therefore, substitute x = 5 into the polynomial to find the value of a.

Substitute x = 5 into the polynomial:
3(5)^2 + a(5) + 4 = 0
75 + 5a + 4 = 0
5a + 79 = 0
5a = -79
a = -79/5
a = -15.8

Conclusion:
The value of a is -15.8, which matches option C.
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If 3x2+ ax + 4 is perfectly divisible by x – 5, then the value of a is:a)-12b)-5c)-15.8d)-15.6Correct answer is option 'C'. Can you explain this answer?
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