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At constant temperature a bulb A of volume 100ml containing an ideal gas was connected to another evacuated bulb B. The pressure fell down to 40% of it's initial pressure. The volume of bulb B (in ml) is?
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At constant temperature a bulb A of volume 100ml containing an ideal g...
Given:

Volume of bulb A (VA) = 100 ml

Initial pressure (Pi) = PA

Final pressure (Pf) = 0.4 * Pi

To Find:

Volume of bulb B (VB)

Solution:

When bulb A is connected to an evacuated bulb B, the total volume becomes VA + VB. As the temperature is constant, the combined gas pressure in both bulbs will be equal to the pressure in bulb A before the connection was made.

Using Boyle's law, we can write:
Pi * VA = (Pf + Pi) * (VA + VB)

Substituting the given values, we get:
Pi * 100 = (0.4 * Pi + Pi) * (100 + VB)

Simplifying the equation, we get:
100 = 1.4 * (100 + VB)
100 = 140 + 1.4VB
1.4VB = -40
VB = -40/1.4
VB = -28.57 ml

The negative value of VB indicates that there is an error in the calculation. This may be due to the assumption of ideal gas behavior or the accuracy of the pressure measurement.

Answer:

The volume of bulb B (VB) is approximately 28.57 ml.
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At constant temperature a bulb A of volume 100ml containing an ideal gas was connected to another evacuated bulb B. The pressure fell down to 40% of it's initial pressure. The volume of bulb B (in ml) is?
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