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Number of bivalents being ten in prophase-1, the number of chromosomes observed in anaphase-2 would be. a)20 b)5 c)10 d)40. Correct answer is 'c'. Can gou explain the answer.?
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Number of bivalents being ten in prophase-1, the number of chromosomes...
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Number of bivalents being ten in prophase-1, the number of chromosomes...
**Explanation:**
During prophase I of meiosis, homologous chromosomes pair up to form bivalents (also known as tetrads). In this case, there are ten bivalents present.
In anaphase II of meiosis, the sister chromatids separate and are pulled to opposite poles of the cell. This results in the division of the bivalents into individual chromosomes.
To determine the number of chromosomes observed in anaphase II, we need to consider two important factors:
1. **Number of chromosomes in a bivalent:** A bivalent consists of two homologous chromosomes, which means it contains two sets of sister chromatids. Therefore, each bivalent contributes two chromosomes.
2. **Number of bivalents:** In this case, there are ten bivalents.
To calculate the total number of chromosomes observed in anaphase II, we multiply the number of bivalents by the number of chromosomes in a bivalent:
Number of chromosomes = Number of bivalents * Number of chromosomes in a bivalent
Number of chromosomes = 10 bivalents * 2 chromosomes per bivalent
Number of chromosomes = 20 chromosomes
Therefore, the correct answer is **20 chromosomes (option a)**.
During prophase I of meiosis, homologous chromosomes pair up to form bivalents (also known as tetrads). In this case, there are ten bivalents present.
In anaphase II of meiosis, the sister chromatids separate and are pulled to opposite poles of the cell. This results in the division of the bivalents into individual chromosomes.
To determine the number of chromosomes observed in anaphase II, we need to consider two important factors:
1. **Number of chromosomes in a bivalent:** A bivalent consists of two homologous chromosomes, which means it contains two sets of sister chromatids. Therefore, each bivalent contributes two chromosomes.
2. **Number of bivalents:** In this case, there are ten bivalents.
To calculate the total number of chromosomes observed in anaphase II, we multiply the number of bivalents by the number of chromosomes in a bivalent:
Number of chromosomes = Number of bivalents * Number of chromosomes in a bivalent
Number of chromosomes = 10 bivalents * 2 chromosomes per bivalent
Number of chromosomes = 20 chromosomes
Therefore, the correct answer is **20 chromosomes (option a)**.
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Number of bivalents being ten in prophase-1, the number of chromosomes observed in anaphase-2 would be. a)20 b)5 c)10 d)40. Correct answer is 'c'. Can gou explain the answer.?
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