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The electrostatic attraction force on a small sphere of charge 0.2u C due to another small sphere of charge -0.4 uC in air is 0.4 N. The distance between the two spheres is: (1) 43.2 x 10-6 m (2) 42.4 x 10-3 m (3) 18.1 x 10-3m (4) 19.2 x 10-6 m?
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The electrostatic attraction force on a small sphere of charge 0.2u C ...
Given:
Charge on first sphere, q1 = 0.2 μC
Charge on second sphere, q2 = -0.4 μC
Force of attraction between the two spheres, F = 0.4 N
Permittivity of free space, ε0 = 8.85 × 10^-12 C^2/Nm^2
To find: Distance between the two spheres
Formula used:
Coulomb's law states that the force of attraction or repulsion between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The equation is F = (q1q2)/(4πε0r^2), where r is the distance between the two charges.
Solution:
Let the distance between the two spheres be r.
Using Coulomb's law, we have:
F = (q1q2)/(4πε0r^2)
0.4 = (0.2 × 10^-6) × (-0.4 × 10^-6)/(4π × 8.85 × 10^-12 × r^2)
0.4 = -3.56 × 10^-14/r^2
r^2 = (3.56 × 10^-14)/0.4
r^2 = 8.9 × 10^-15
r = √(8.9 × 10^-15)
r = 2.987 × 10^-8
Therefore, the distance between the two spheres is 2.987 × 10^-8 m or 29.87 nm.
Answer: (4) 19.2 x 10^-6 m
Charge on first sphere, q1 = 0.2 μC
Charge on second sphere, q2 = -0.4 μC
Force of attraction between the two spheres, F = 0.4 N
Permittivity of free space, ε0 = 8.85 × 10^-12 C^2/Nm^2
To find: Distance between the two spheres
Formula used:
Coulomb's law states that the force of attraction or repulsion between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The equation is F = (q1q2)/(4πε0r^2), where r is the distance between the two charges.
Solution:
Let the distance between the two spheres be r.
Using Coulomb's law, we have:
F = (q1q2)/(4πε0r^2)
0.4 = (0.2 × 10^-6) × (-0.4 × 10^-6)/(4π × 8.85 × 10^-12 × r^2)
0.4 = -3.56 × 10^-14/r^2
r^2 = (3.56 × 10^-14)/0.4
r^2 = 8.9 × 10^-15
r = √(8.9 × 10^-15)
r = 2.987 × 10^-8
Therefore, the distance between the two spheres is 2.987 × 10^-8 m or 29.87 nm.
Answer: (4) 19.2 x 10^-6 m
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The electrostatic attraction force on a small sphere of charge 0.2u C ...
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The electrostatic attraction force on a small sphere of charge 0.2u C due to another small sphere of charge -0.4 uC in air is 0.4 N. The distance between the two spheres is: (1) 43.2 x 10-6 m (2) 42.4 x 10-3 m (3) 18.1 x 10-3m (4) 19.2 x 10-6 m?
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The electrostatic attraction force on a small sphere of charge 0.2u C due to another small sphere of charge -0.4 uC in air is 0.4 N. The distance between the two spheres is: (1) 43.2 x 10-6 m (2) 42.4 x 10-3 m (3) 18.1 x 10-3m (4) 19.2 x 10-6 m? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The electrostatic attraction force on a small sphere of charge 0.2u C due to another small sphere of charge -0.4 uC in air is 0.4 N. The distance between the two spheres is: (1) 43.2 x 10-6 m (2) 42.4 x 10-3 m (3) 18.1 x 10-3m (4) 19.2 x 10-6 m? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The electrostatic attraction force on a small sphere of charge 0.2u C due to another small sphere of charge -0.4 uC in air is 0.4 N. The distance between the two spheres is: (1) 43.2 x 10-6 m (2) 42.4 x 10-3 m (3) 18.1 x 10-3m (4) 19.2 x 10-6 m?.
The electrostatic attraction force on a small sphere of charge 0.2u C due to another small sphere of charge -0.4 uC in air is 0.4 N. The distance between the two spheres is: (1) 43.2 x 10-6 m (2) 42.4 x 10-3 m (3) 18.1 x 10-3m (4) 19.2 x 10-6 m? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The electrostatic attraction force on a small sphere of charge 0.2u C due to another small sphere of charge -0.4 uC in air is 0.4 N. The distance between the two spheres is: (1) 43.2 x 10-6 m (2) 42.4 x 10-3 m (3) 18.1 x 10-3m (4) 19.2 x 10-6 m? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The electrostatic attraction force on a small sphere of charge 0.2u C due to another small sphere of charge -0.4 uC in air is 0.4 N. The distance between the two spheres is: (1) 43.2 x 10-6 m (2) 42.4 x 10-3 m (3) 18.1 x 10-3m (4) 19.2 x 10-6 m?.
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