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Two small charged spheres having charges of 2 * 10 ^ - 7 * C and 3 * 10 ^ - 7 * C are placed 3cm apart in vacuum. Find the electrostatic force between them. Find the new force, when the distance between them is doubled.?
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Two small charged spheres having charges of 2 * 10 ^ - 7 * C and 3 * 1...
Calculation of Electrostatic Force
Given, the charges of the spheres are q1 = 2 * 10 ^ - 7 * C and q2 = 3 * 10 ^ - 7 * C
The distance between the spheres is d = 3cm = 0.03m
The electrostatic force between two charged spheres is given by Coulomb's Law:
F = (1 / 4πε0) * (q1 * q2) / d2
where ε0 is the permittivity of free space, which is equal to 8.85 * 10^-12 C^2/(N*m^2).
Substituting the given values in the above equation, we get:
F = (1 / 4πε0) * (2 * 10 ^ - 7 * 3 * 10 ^ - 7) / (0.03) ^ 2 N
F = 2.4 * 10 ^ - 11 N
Calculation of New Electrostatic Force
When the distance between the spheres is doubled, the new distance between them is 2d = 0.06m.
The electrostatic force between the spheres is given by Coulomb's Law:
F = (1 / 4πε0) * (q1 * q2) / (2d)2
Substituting the given values in the above equation, we get:
F = (1 / 4πε0) * (2 * 10 ^ - 7 * 3 * 10 ^ - 7) / (0.06) ^ 2 N
F = 6 * 10 ^ - 12 N
Explanation
When the distance between the two spheres is doubled, the electrostatic force between them decreases by a factor of four. This is because the electrostatic force is inversely proportional to the square of the distance between the charges. Therefore, as the distance between the charges increases, the force between them decreases.
Community Answer
Two small charged spheres having charges of 2 * 10 ^ - 7 * C and 3 * 1...
Calculation of Electrostatic Force
Given, the charges of the two spheres are q1 = 2 * 10-7 C and q2 = 3 * 10-7 C and the distance between them is d = 3 cm = 0.03 m. The electrostatic force between them is given by Coulomb's law:
F = (1/4πε0) * (q1 * q2) / d2
where ε0 is the permittivity of vacuum, which is a constant with a value of 8.854 * 10-12 C2 / Nm2.
Substituting the given values, we get:
F = (1/4πε0) * (2 * 10-7 * 3 * 10-7) / (0.03)2
F = 1.2 * 10-16 N
Calculation of New Electrostatic Force
When the distance between the two spheres is doubled, i.e., d' = 2d = 0.06 m, the electrostatic force between them can be calculated using the same formula:
F' = (1/4πε0) * (q1 * q2) / d'2
Substituting the given values, we get:
F' = (1/4πε0) * (2 * 10-7 * 3 * 10-7) / (0.06)2
F' = 3 * 10-17 N
Explanation
Electrostatic force is the force between two charged objects due to their charges and the distance between them. Coulomb's law gives us a way to calculate this force for point charges. The force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
In this problem, we were given the charges of two small spheres and the distance between them. Using Coulomb's law, we found the electrostatic force between them to be 1.2 * 10-16 N. When the distance between them was doubled, we found the new electrostatic force to be 3 * 10-17 N.
This shows that the electrostatic force decreases as the distance between the charged objects increases. When the distance is doubled, the force becomes one-fourth of its original value. This is because the force is inversely proportional to
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Two small charged spheres having charges of 2 * 10 ^ - 7 * C and 3 * 10 ^ - 7 * C are placed 3cm apart in vacuum. Find the electrostatic force between them. Find the new force, when the distance between them is doubled.?
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Two small charged spheres having charges of 2 * 10 ^ - 7 * C and 3 * 10 ^ - 7 * C are placed 3cm apart in vacuum. Find the electrostatic force between them. Find the new force, when the distance between them is doubled.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two small charged spheres having charges of 2 * 10 ^ - 7 * C and 3 * 10 ^ - 7 * C are placed 3cm apart in vacuum. Find the electrostatic force between them. Find the new force, when the distance between them is doubled.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two small charged spheres having charges of 2 * 10 ^ - 7 * C and 3 * 10 ^ - 7 * C are placed 3cm apart in vacuum. Find the electrostatic force between them. Find the new force, when the distance between them is doubled.?.
Two small charged spheres having charges of 2 * 10 ^ - 7 * C and 3 * 10 ^ - 7 * C are placed 3cm apart in vacuum. Find the electrostatic force between them. Find the new force, when the distance between them is doubled.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two small charged spheres having charges of 2 * 10 ^ - 7 * C and 3 * 10 ^ - 7 * C are placed 3cm apart in vacuum. Find the electrostatic force between them. Find the new force, when the distance between them is doubled.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two small charged spheres having charges of 2 * 10 ^ - 7 * C and 3 * 10 ^ - 7 * C are placed 3cm apart in vacuum. Find the electrostatic force between them. Find the new force, when the distance between them is doubled.?.
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