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A point object is placed at a distance of 1000 mm from a concave mirror of focal length 400 mm. If the object is moved towards the mirror by 200 mm, the image moves by a distance of
- a)133.3 mm towards mirror
- b)133.3 mm away from the mirror
- c)30 mm towards mirror
- d)30 mm away from the mirror
Correct answer is option 'B'. Can you explain this answer?
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Explanation:
When an object is placed at a distance of 1000 mm from a concave mirror of focal length 400 mm, we can find the position of the image formed by using the mirror formula:
$\frac{1}{v}-\frac{1}{u}=\frac{1}{f}$
where,
v = distance of image from mirror
u = distance of object from mirror
f = focal length of the mirror
Substituting the given values, we get:
$\frac{1}{v}-\frac{1}{1000}=\frac{1}{400}$
Solving for v, we get:
v = - 1500 mm
The negative sign indicates that the image is formed behind the mirror (i.e., it is a virtual image).
When the object is moved towards the mirror by 200 mm, the new distance of the object from the mirror is u' = 800 mm. Using the same formula, we can find the new position of the image:
$\frac{1}{v'}-\frac{1}{800}=\frac{1}{400}$
Solving for v', we get:
v' = - 1200 mm
The negative sign indicates that the image is still formed behind the mirror (i.e., it is still a virtual image).
Therefore, the image moves away from the mirror by a distance of:
$\Delta$ v = v' - v = -1200 - (-1500) = 300 mm
Since the image is formed behind the mirror, a movement away from the mirror is equivalent to a movement towards the object. Hence, the correct answer is option B, i.e., the image moves by a distance of 133.3 mm away from the mirror.
When an object is placed at a distance of 1000 mm from a concave mirror of focal length 400 mm, we can find the position of the image formed by using the mirror formula:
$\frac{1}{v}-\frac{1}{u}=\frac{1}{f}$
where,
v = distance of image from mirror
u = distance of object from mirror
f = focal length of the mirror
Substituting the given values, we get:
$\frac{1}{v}-\frac{1}{1000}=\frac{1}{400}$
Solving for v, we get:
v = - 1500 mm
The negative sign indicates that the image is formed behind the mirror (i.e., it is a virtual image).
When the object is moved towards the mirror by 200 mm, the new distance of the object from the mirror is u' = 800 mm. Using the same formula, we can find the new position of the image:
$\frac{1}{v'}-\frac{1}{800}=\frac{1}{400}$
Solving for v', we get:
v' = - 1200 mm
The negative sign indicates that the image is still formed behind the mirror (i.e., it is still a virtual image).
Therefore, the image moves away from the mirror by a distance of:
$\Delta$ v = v' - v = -1200 - (-1500) = 300 mm
Since the image is formed behind the mirror, a movement away from the mirror is equivalent to a movement towards the object. Hence, the correct answer is option B, i.e., the image moves by a distance of 133.3 mm away from the mirror.
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A point object is placed at a distance of 1000 mm from a concave mirror of focal length 400 mm. If the object is moved towards the mirror by 200 mm, the image moves by a distance ofa)133.3 mm towards mirrorb)133.3 mm away from the mirrorc)30 mm towards mirrord)30 mm away from the mirrorCorrect answer is option 'B'. Can you explain this answer?
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A point object is placed at a distance of 1000 mm from a concave mirror of focal length 400 mm. If the object is moved towards the mirror by 200 mm, the image moves by a distance ofa)133.3 mm towards mirrorb)133.3 mm away from the mirrorc)30 mm towards mirrord)30 mm away from the mirrorCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A point object is placed at a distance of 1000 mm from a concave mirror of focal length 400 mm. If the object is moved towards the mirror by 200 mm, the image moves by a distance ofa)133.3 mm towards mirrorb)133.3 mm away from the mirrorc)30 mm towards mirrord)30 mm away from the mirrorCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A point object is placed at a distance of 1000 mm from a concave mirror of focal length 400 mm. If the object is moved towards the mirror by 200 mm, the image moves by a distance ofa)133.3 mm towards mirrorb)133.3 mm away from the mirrorc)30 mm towards mirrord)30 mm away from the mirrorCorrect answer is option 'B'. Can you explain this answer?.
A point object is placed at a distance of 1000 mm from a concave mirror of focal length 400 mm. If the object is moved towards the mirror by 200 mm, the image moves by a distance ofa)133.3 mm towards mirrorb)133.3 mm away from the mirrorc)30 mm towards mirrord)30 mm away from the mirrorCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A point object is placed at a distance of 1000 mm from a concave mirror of focal length 400 mm. If the object is moved towards the mirror by 200 mm, the image moves by a distance ofa)133.3 mm towards mirrorb)133.3 mm away from the mirrorc)30 mm towards mirrord)30 mm away from the mirrorCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A point object is placed at a distance of 1000 mm from a concave mirror of focal length 400 mm. If the object is moved towards the mirror by 200 mm, the image moves by a distance ofa)133.3 mm towards mirrorb)133.3 mm away from the mirrorc)30 mm towards mirrord)30 mm away from the mirrorCorrect answer is option 'B'. Can you explain this answer?.
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