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Point charge +4q, -q and +4q are kept on the x-axis at points x = 0, x = a and x = 2a respectively. Then:
  • a)
    only -q is in stable equilibrium
  • b)
    none of the charges are in equilibrium
  • c)
    all the charges are in unstable equilibrium
  • d)
    all the charges are in stable equilibrium
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Point charge +4q, -q and +4q are kept on the x-axis at points x = 0, x...
Explanation:

  • When a charge is placed in an electric field, it experiences a force.

  • The direction of the force depends on the sign of the charge and the direction of the electric field.

  • If the net force on a charge is zero, the charge is said to be in equilibrium.

  • If the net force is directed towards the equilibrium position, the equilibrium is said to be stable.

  • If the net force is directed away from the equilibrium position, the equilibrium is said to be unstable.

  • In this case, the charge at x=0 experiences repulsive forces from the charges at x=a and 2a.

  • Similarly, the charge at x=2a also experiences repulsive forces from the charges at x=0 and a.

  • Therefore, these charges are in unstable equilibrium.

  • The charge at x=a experiences attractive force from the charge at x=0 and repulsive force from the charge at x=2a.

  • Thus, this charge is also in unstable equilibrium.

  • Therefore, all the charges are in unstable equilibrium.

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Point charge +4q, -q and +4q are kept on the x-axis at points x = 0, x...
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Point charge +4q, -q and +4q are kept on the x-axis at points x = 0, x = a and x = 2a respectively. Then:a)only -q is in stable equilibriumb)none of the charges are in equilibriumc)all the charges are in unstable equilibriumd)all the charges are in stable equilibriumCorrect answer is option 'C'. Can you explain this answer?
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