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If pkb for fluoride ion at 25c is 10.83,the ionisation constant for hydrofluoric acid in water at temperature is A .1.74×10−3 B .3.52×10−3 C 6.75×10−4 D 5.38×10−2 Ans is c Can anyone plz explain thiz question ?
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Calculation of Hydrogen Fluoride Ionization Constant

PKb for Fluoride Ion

- PKb is the negative logarithm of the base ionization constant (Kb) of a conjugate base.
- The given PKb for fluoride ion at 25°C is 10.83.

PKa for Hydrogen Fluoride

- PKa is the negative logarithm of the acid ionization constant (Ka) of an acid.
- The acid in this case is hydrogen fluoride (HF).
- To calculate PKa, we can use the relationship: PKa + PKb = 14 (at 25°C).
- Therefore, PKa = 14 - PKb = 14 - 10.83 = 3.17.

Ionization Constant for Hydrogen Fluoride

- The ionization constant for hydrogen fluoride (Ka) in water at temperature can be calculated using the following equation:
- Ka = [H+][F-]/[HF]
- At equilibrium, the concentration of HF is equal to the initial concentration minus the concentration of H+ ions (assuming complete ionization).
- The concentration of F- ions is equal to the concentration of H+ ions (assuming complete ionization).
- The concentration of H+ ions can be calculated using the equation for the dissociation of water: Kw = [H+][OH-] = 1.0 x 10^-14.
- At 25°C, Kw = 1.0 x 10^-14, and the concentration of OH- ions is equal to the concentration of H+ ions.
- Therefore, [H+] = [OH-] = sqrt(Kw) = sqrt(1.0 x 10^-14) = 1.0 x 10^-7.
- Substituting the values into the equation for Ka, we get: Ka = (1.0 x 10^-7)(1.0 x 10^-7)/(1.0 - 1.0 x 10^-7) = 6.75 x 10^-4.

Answer

- The ionization constant for hydrogen fluoride in water at temperature is 6.75 x 10^-4.
- The correct answer is option C.
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If pkb for fluoride ion at 25c is 10.83,the ionisation constant for hydrofluoric acid in water at temperature is A .1.74×10−3 B .3.52×10−3 C 6.75×10−4 D 5.38×10−2 Ans is c Can anyone plz explain thiz question ?
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If pkb for fluoride ion at 25c is 10.83,the ionisation constant for hydrofluoric acid in water at temperature is A .1.74×10−3 B .3.52×10−3 C 6.75×10−4 D 5.38×10−2 Ans is c Can anyone plz explain thiz question ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If pkb for fluoride ion at 25c is 10.83,the ionisation constant for hydrofluoric acid in water at temperature is A .1.74×10−3 B .3.52×10−3 C 6.75×10−4 D 5.38×10−2 Ans is c Can anyone plz explain thiz question ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If pkb for fluoride ion at 25c is 10.83,the ionisation constant for hydrofluoric acid in water at temperature is A .1.74×10−3 B .3.52×10−3 C 6.75×10−4 D 5.38×10−2 Ans is c Can anyone plz explain thiz question ?.
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