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A bullet hits and gets embedded in a solid block resting on frictionless surface. In this process which one of the following is correct?
- a)Only momentum is conserved.
- b)Only kinetic energy is conserved.
- c)Neither momentum nor kinetic energy is conserved.
- d)Both momentum and kinetic energy are conserved.
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
A bullet hits and gets embedded in a solid block resting on frictionle...
Since no external force is acting on the bullet + solid system when a bullet gets embedded in the solid, thus total momentum of the system is conserved.
But total kinetic energy of the system is not conserved as it is a perfectly inelastic collision and some kinetic energy is lost as heat. So ans first is correct..
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A bullet hits and gets embedded in a solid block resting on frictionle...
Conservation of Momentum:
When a bullet hits a solid block, the total momentum before the collision is equal to the total momentum after the collision, assuming no external forces are acting on the system. This is known as the principle of conservation of momentum.
Explanation:
When the bullet hits the block, it imparts a certain amount of momentum to the block. The bullet and the block are initially at rest, so the total momentum before the collision is zero. After the collision, the bullet gets embedded in the block, and they move together as a single object. Therefore, the total momentum after the collision is also zero.
Mathematical Representation:
Let the mass of the bullet be m1 and its initial velocity be v1. The mass of the block is m2, and its initial velocity is 0. The final velocity of the combined bullet-block system is v.
Before collision:
Total momentum = m1v1 + m2(0) = m1v1
After collision:
Total momentum = (m1 + m2)v = 0
Since the total momentum before and after the collision is equal to zero, we can conclude that momentum is conserved in this process.
Conservation of Kinetic Energy:
However, kinetic energy is not conserved in this process. Kinetic energy is equal to (1/2)mv^2, where m is the mass and v is the velocity of an object. Before the collision, the bullet has kinetic energy due to its motion, but the block is at rest, so its kinetic energy is zero. After the collision, the bullet gets embedded in the block, and they move together. The combined bullet-block system now has kinetic energy due to its motion.
Conclusion:
In summary, when a bullet hits and gets embedded in a solid block resting on a frictionless surface, momentum is conserved (option A), but kinetic energy is not conserved (option B).
When a bullet hits a solid block, the total momentum before the collision is equal to the total momentum after the collision, assuming no external forces are acting on the system. This is known as the principle of conservation of momentum.
Explanation:
When the bullet hits the block, it imparts a certain amount of momentum to the block. The bullet and the block are initially at rest, so the total momentum before the collision is zero. After the collision, the bullet gets embedded in the block, and they move together as a single object. Therefore, the total momentum after the collision is also zero.
Mathematical Representation:
Let the mass of the bullet be m1 and its initial velocity be v1. The mass of the block is m2, and its initial velocity is 0. The final velocity of the combined bullet-block system is v.
Before collision:
Total momentum = m1v1 + m2(0) = m1v1
After collision:
Total momentum = (m1 + m2)v = 0
Since the total momentum before and after the collision is equal to zero, we can conclude that momentum is conserved in this process.
Conservation of Kinetic Energy:
However, kinetic energy is not conserved in this process. Kinetic energy is equal to (1/2)mv^2, where m is the mass and v is the velocity of an object. Before the collision, the bullet has kinetic energy due to its motion, but the block is at rest, so its kinetic energy is zero. After the collision, the bullet gets embedded in the block, and they move together. The combined bullet-block system now has kinetic energy due to its motion.
Conclusion:
In summary, when a bullet hits and gets embedded in a solid block resting on a frictionless surface, momentum is conserved (option A), but kinetic energy is not conserved (option B).
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A bullet hits and gets embedded in a solid block resting on frictionless surface. In this process which one of the following is correct?a)Only momentum is conserved.b)Only kinetic energy is conserved.c)Neither momentum nor kinetic energy is conserved.d)Both momentum and kinetic energy are conserved.Correct answer is option 'A'. Can you explain this answer?
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A bullet hits and gets embedded in a solid block resting on frictionless surface. In this process which one of the following is correct?a)Only momentum is conserved.b)Only kinetic energy is conserved.c)Neither momentum nor kinetic energy is conserved.d)Both momentum and kinetic energy are conserved.Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A bullet hits and gets embedded in a solid block resting on frictionless surface. In this process which one of the following is correct?a)Only momentum is conserved.b)Only kinetic energy is conserved.c)Neither momentum nor kinetic energy is conserved.d)Both momentum and kinetic energy are conserved.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bullet hits and gets embedded in a solid block resting on frictionless surface. In this process which one of the following is correct?a)Only momentum is conserved.b)Only kinetic energy is conserved.c)Neither momentum nor kinetic energy is conserved.d)Both momentum and kinetic energy are conserved.Correct answer is option 'A'. Can you explain this answer?.
A bullet hits and gets embedded in a solid block resting on frictionless surface. In this process which one of the following is correct?a)Only momentum is conserved.b)Only kinetic energy is conserved.c)Neither momentum nor kinetic energy is conserved.d)Both momentum and kinetic energy are conserved.Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A bullet hits and gets embedded in a solid block resting on frictionless surface. In this process which one of the following is correct?a)Only momentum is conserved.b)Only kinetic energy is conserved.c)Neither momentum nor kinetic energy is conserved.d)Both momentum and kinetic energy are conserved.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bullet hits and gets embedded in a solid block resting on frictionless surface. In this process which one of the following is correct?a)Only momentum is conserved.b)Only kinetic energy is conserved.c)Neither momentum nor kinetic energy is conserved.d)Both momentum and kinetic energy are conserved.Correct answer is option 'A'. Can you explain this answer?.
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