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On adding KI to a solution of CuSO₄
- a)Cupric oxide is precipitated
- b)Metallic copper is precipitated
- c)Cuprous iodide is precipitated with the liberation of iodine
- d)No change takes place
Correct answer is option 'C'. Can you explain this answer?
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On adding KI to a solution of CuSOa)Cupric oxide is precipitatedb)Meta...
There is an interesting redox reaction which occurs when the iodide ion will reduce the copper(II) ion to copper(I) while iodide itself is oxidized to elemental iodine. Like most copper(I) compounds, CuI is insoluble in water.
4KI(aq)+2CuSO4(aq)→Cu2I2(s)+I2(s)+2K2SO4(aq)
4KI(aq)+2CuSO4(aq)→Cu2I2(s)+I2(s)+2K2SO4(aq)
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On adding KI to a solution of CuSOa)Cupric oxide is precipitatedb)Metallic copper is precipitatedc)Cuprous iodide is precipitated with the liberation of iodined)No change takes placeCorrect answer is option 'C'. Can you explain this answer?
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