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Ni(nh3)2(cl)2=hybridization geometry and reason for not showing geometrical isomerism?
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Ni(nh3)2(cl)2=hybridization geometry and reason for not showing geomet...
**Hybridization Geometry of Ni(NH3)2Cl2:**
The compound Ni(NH3)2Cl2 consists of a central nickel (Ni) atom bonded to two ammonia (NH3) ligands and two chloride (Cl) ligands. To determine the hybridization geometry of the compound, we need to consider the electron pair geometry and the number of hybrid orbitals formed.
1. Electron Pair Geometry:
The electron pair geometry is determined by the number of electron pairs around the central atom. In this case, each ammonia ligand contributes one electron pair, and each chloride ligand contributes three electron pairs. Therefore, there are a total of 8 electron pairs around the central nickel atom.
2. Hybridization:
Nickel has the electron configuration [Ar] 3d8 4s2, and it can undergo hybridization to form the necessary number of orbitals for bonding. In the case of Ni(NH3)2Cl2, the nickel atom undergoes sp3d2 hybridization.
3. Hybrid Orbitals:
The sp3d2 hybridization results in the formation of six hybrid orbitals. These orbitals are composed of one 3s, three 3p, and two 3d orbitals. The six hybrid orbitals are arranged in an octahedral geometry around the central nickel atom.
**Reason for Not Showing Geometrical Isomerism:**
Geometrical isomerism occurs when two or more compounds have the same molecular formula but differ in the arrangement of their atoms in space. In the case of Ni(NH3)2Cl2, there is no geometrical isomerism observed due to the following reasons:
1. Ligand Arrangement:
The ammonia (NH3) and chloride (Cl) ligands are both monodentate, meaning they form a single bond with the central nickel atom. As a result, the ligands can arrange themselves in a trans configuration, with the two ammonia ligands opposite to each other and the two chloride ligands opposite to each other.
2. No Additional Ligands:
In order for geometrical isomerism to occur, there needs to be at least two different ligands bonded to the central atom. In the case of Ni(NH3)2Cl2, all the ligands are the same (ammonia and chloride), and there are no other ligands present. Therefore, there are no different arrangements of ligands that can lead to geometrical isomerism.
3. Symmetrical Structure:
The trans arrangement of the ligands in Ni(NH3)2Cl2 results in a symmetrical structure. The compound possesses a plane of symmetry, which means that any attempt to rotate the molecule along the plane of symmetry will result in the same configuration. This symmetry further eliminates the possibility of geometrical isomerism.
In conclusion, Ni(NH3)2Cl2 exhibits an octahedral hybridization geometry due to sp3d2 hybrid orbitals. The compound does not show geometrical isomerism because of the trans arrangement of identical ligands, the absence of additional ligands, and the presence of a plane of symmetry.
The compound Ni(NH3)2Cl2 consists of a central nickel (Ni) atom bonded to two ammonia (NH3) ligands and two chloride (Cl) ligands. To determine the hybridization geometry of the compound, we need to consider the electron pair geometry and the number of hybrid orbitals formed.
1. Electron Pair Geometry:
The electron pair geometry is determined by the number of electron pairs around the central atom. In this case, each ammonia ligand contributes one electron pair, and each chloride ligand contributes three electron pairs. Therefore, there are a total of 8 electron pairs around the central nickel atom.
2. Hybridization:
Nickel has the electron configuration [Ar] 3d8 4s2, and it can undergo hybridization to form the necessary number of orbitals for bonding. In the case of Ni(NH3)2Cl2, the nickel atom undergoes sp3d2 hybridization.
3. Hybrid Orbitals:
The sp3d2 hybridization results in the formation of six hybrid orbitals. These orbitals are composed of one 3s, three 3p, and two 3d orbitals. The six hybrid orbitals are arranged in an octahedral geometry around the central nickel atom.
**Reason for Not Showing Geometrical Isomerism:**
Geometrical isomerism occurs when two or more compounds have the same molecular formula but differ in the arrangement of their atoms in space. In the case of Ni(NH3)2Cl2, there is no geometrical isomerism observed due to the following reasons:
1. Ligand Arrangement:
The ammonia (NH3) and chloride (Cl) ligands are both monodentate, meaning they form a single bond with the central nickel atom. As a result, the ligands can arrange themselves in a trans configuration, with the two ammonia ligands opposite to each other and the two chloride ligands opposite to each other.
2. No Additional Ligands:
In order for geometrical isomerism to occur, there needs to be at least two different ligands bonded to the central atom. In the case of Ni(NH3)2Cl2, all the ligands are the same (ammonia and chloride), and there are no other ligands present. Therefore, there are no different arrangements of ligands that can lead to geometrical isomerism.
3. Symmetrical Structure:
The trans arrangement of the ligands in Ni(NH3)2Cl2 results in a symmetrical structure. The compound possesses a plane of symmetry, which means that any attempt to rotate the molecule along the plane of symmetry will result in the same configuration. This symmetry further eliminates the possibility of geometrical isomerism.
In conclusion, Ni(NH3)2Cl2 exhibits an octahedral hybridization geometry due to sp3d2 hybrid orbitals. The compound does not show geometrical isomerism because of the trans arrangement of identical ligands, the absence of additional ligands, and the presence of a plane of symmetry.
Community Answer
Ni(nh3)2(cl)2=hybridization geometry and reason for not showing geomet...
It won't show geometry because its paired geometry is majorly shown by unpaired
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Ni(nh3)2(cl)2=hybridization geometry and reason for not showing geometrical isomerism? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Ni(nh3)2(cl)2=hybridization geometry and reason for not showing geometrical isomerism? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ni(nh3)2(cl)2=hybridization geometry and reason for not showing geometrical isomerism?.
Ni(nh3)2(cl)2=hybridization geometry and reason for not showing geometrical isomerism? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Ni(nh3)2(cl)2=hybridization geometry and reason for not showing geometrical isomerism? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ni(nh3)2(cl)2=hybridization geometry and reason for not showing geometrical isomerism?.
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