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If 13.6ev energy is required to ionize the hydrogen atom,then the energy required to remove an electron from its first excited state is A)10.2ev B)5.1ev C)3.4ev D)6.8ev They given "C" option can you plz explain?
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Calculation of the energy required to remove an electron from the first excited state of a hydrogen atom


To calculate the energy required to remove an electron from the first excited state of a hydrogen atom, we need to consider the energy levels of the hydrogen atom and the energy difference between these levels.

Here are the key points to consider:

1. Energy levels of the hydrogen atom:
- The ground state of a hydrogen atom is when the electron is in the lowest energy level, called the n=1 level.
- The first excited state is when the electron is in the n=2 level, which is a higher energy level than the ground state.

2. Energy difference between the levels:
- The energy difference between any two levels of a hydrogen atom can be calculated using the formula:
ΔE = 13.6/n^2 (in electron volts)
where ΔE is the energy difference and n is the principal quantum number of the higher energy level.

Now, let's calculate the energy required to remove an electron from the first excited state (n=2) of the hydrogen atom:

- Substitute n=2 into the formula:
ΔE = 13.6/2^2 = 13.6/4 = 3.4 eV

Therefore, the energy required to remove an electron from the first excited state of a hydrogen atom is 3.4 eV.

Answer

The correct option is C) 3.4 eV.
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If 13.6ev energy is required to ionize the hydrogen atom,then the energy required to remove an electron from its first excited state is A)10.2ev B)5.1ev C)3.4ev D)6.8ev They given "C" option can you plz explain?
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