4 are possible 1) 1-(2chlorophenyl) 1-phenyl methane2) 1-(3chlorophenyl) 1-phenyl methane3) 1-(4chlorophenyl) 1-phenyl methane4) 1-chloro 1,1-diphenyl methane

Number of Structural Isomers in Diphenylmethane with Chlorine Replacement

To determine the number of structural isomers that can be formed when one of the hydrogen atoms in diphenylmethane (C6H5CH2H) is replaced by a chlorine atom (Cl), we need to consider the different possible positions for the chlorine substitution. The chlorine atom can potentially replace any of the three hydrogen atoms in diphenylmethane.

1. Chlorine Substituting the Hydrogen Atom in the Phenyl Group (Aromatic Ring)
When chlorine replaces one of the hydrogen atoms in either of the phenyl groups, it results in the formation of a different structural isomer. There are two possible positions for this substitution:
- Chlorine can replace the hydrogen atom in the first phenyl group (C6H5CH(Cl)H)
- Chlorine can replace the hydrogen atom in the second phenyl group (C6H5C(H)ClH)

2. Chlorine Substituting the Hydrogen Atom in the Methylene Group
When chlorine replaces the hydrogen atom in the methylene group (CH2), it also results in the formation of a different structural isomer. There is only one possible position for this substitution:
- Chlorine can replace the hydrogen atom in the methylene group (C6H5C(Cl)H2)

Combining the Possibilities
Since there are two possible positions for chlorine substitution in the phenyl group and one possible position in the methylene group, we can multiply the number of possibilities for each position to obtain the total number of structural isomers.

Total number of structural isomers = Number of possibilities in phenyl group x Number of possibilities in methylene group

Total number of structural isomers = 2 x 1 = 2

Therefore, when one of the hydrogen atoms in diphenylmethane is replaced by a chlorine atom, there are a total of 2 structural isomers that can be formed.