The weight of silver (at. wt. = 108) displaced by a quantity of electr...
Weight of silver/eq.atomic mass= volume of O2/ eq.volume , here eq volume of O2 at STP is 22.4/2 =11.2lit and eq.atomic weight of Ag is 108/1=108 , then weight of the silver/108= 5.6lit/11.2lit ,. weight of the silver/108= 1/2 , weight of the silver= 108/2 =54gm
The weight of silver (at. wt. = 108) displaced by a quantity of electr...
Calculating the Weight of Silver Displaced
To calculate the weight of silver displaced by the given quantity of electricity, we can use Faraday's laws of electrolysis. According to Faraday's law, the amount of substance deposited at an electrode is directly proportional to the quantity of electricity passed through the electrolyte.
Given Information:
- Volume of O2 displaced = 5600 mL
- Silver atomic weight (at. wt.) = 108
Step 1: Calculate the moles of O2 displaced
- Using the ideal gas law: PV = nRT
- Since the volume is given at STP (standard temperature and pressure), we can substitute the values:
- P = 1 atm
- V = 5600 mL = 5.6 L
- T = 273 K
- R = 0.0821 L.atm/mol.K
- Solve for n (moles of O2)
Step 2: Calculate the charge passed
- Since 1 mole of O2 requires 4 moles of electrons for electrolysis
- Determine the total charge passed through the electrolyte
Step 3: Calculate the moles of silver deposited
- Using Faraday's law, determine the moles of silver deposited
Step 4: Calculate the weight of silver displaced
- Finally, calculate the weight of silver displaced using the atomic weight of silver
Answer:
The weight of silver displaced by the given quantity of electricity will be 10.8 g (Option B).
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