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The time required for 60% completion of a first order reaction is 50 minutes. The time required for 93.5% completion of the same reaction will be a) 100 min b) 83.8 min. c) 50 min. d) 150 min.?
Most Upvoted Answer
The time required for 60% completion of a first order reaction is 50 m...
Solution:
Given that for a first-order reaction:
t(60%) = 50 min
We need to find t(93.5%)
We know that the time required for a reaction to reach a certain percentage completion is inversely proportional to the rate constant of the reaction.
Therefore, we can use the following relation:
t(60%)/t(93.5%) = (ln 2)/(ln 1 - 0.6) = 1.609
Solving for t(93.5%):
t(93.5%) = t(60%)/1.609 = 31.09 × 1.609 = 50 min

Therefore, the correct option is c) 50 min.

Explanation:
The question is based on the concept of first-order reactions and the relation between the time required for a certain percentage completion of the reaction and the rate constant of the reaction. The solution involves the use of the relation between the time required for 60% and 93.5% completion of the reaction and the rate constant of the reaction. The answer is obtained by applying the relation and solving for the required time.
Community Answer
The time required for 60% completion of a first order reaction is 50 m...
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The time required for 60% completion of a first order reaction is 50 minutes. The time required for 93.5% completion of the same reaction will be a) 100 min b) 83.8 min. c) 50 min. d) 150 min.?
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