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fundamental frequency of an open organ pipe is 1400Hz . if its 30% length is immersed in water then calculate new frequency of open organ pipe ? pls explain the ans.
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fundamental frequency of an open organ pipe is 1400Hz . if its 30% len...
Fundamental Frequency of an Open Organ Pipe
The fundamental frequency of an open organ pipe is determined by its length and the speed of sound in the medium it is in. When the pipe is open at both ends, the fundamental frequency is given by the equation:
f = v / (2L)
Where:
- f is the fundamental frequency
- v is the speed of sound
- L is the length of the pipe
The equation shows that the fundamental frequency is inversely proportional to the length of the pipe. In other words, as the length of the pipe increases, the frequency decreases.
Effect of Immersion in Water
When a portion of the open organ pipe is immersed in water, the effective length of the pipe changes. This change in length affects the fundamental frequency of the pipe.
In this case, if 30% of the length of the pipe is immersed in water, the effective length of the pipe will be reduced by 30%. Let's assume the initial length of the pipe is given by L0 and the immersed length is given by 0.3L0.
The new length of the pipe, L, can be calculated by subtracting the immersed length from the initial length:
L = L0 - 0.3L0 = 0.7L0
Calculating the New Frequency
Using the new length of the pipe, we can calculate the new fundamental frequency using the same equation as before:
f' = v / (2L)
Substituting L with 0.7L0:
f' = v / (2 * 0.7L0) = (5/7) * (v / (2L0)) = (5/7) * f
Therefore, the new frequency f' is equal to (5/7) times the initial frequency f.
Conclusion
In conclusion, when 30% of the length of an open organ pipe is immersed in water, the new frequency of the pipe is (5/7) times the initial frequency. This change in frequency is due to the change in effective length caused by the immersion in water.
The fundamental frequency of an open organ pipe is determined by its length and the speed of sound in the medium it is in. When the pipe is open at both ends, the fundamental frequency is given by the equation:
f = v / (2L)
Where:
- f is the fundamental frequency
- v is the speed of sound
- L is the length of the pipe
The equation shows that the fundamental frequency is inversely proportional to the length of the pipe. In other words, as the length of the pipe increases, the frequency decreases.
Effect of Immersion in Water
When a portion of the open organ pipe is immersed in water, the effective length of the pipe changes. This change in length affects the fundamental frequency of the pipe.
In this case, if 30% of the length of the pipe is immersed in water, the effective length of the pipe will be reduced by 30%. Let's assume the initial length of the pipe is given by L0 and the immersed length is given by 0.3L0.
The new length of the pipe, L, can be calculated by subtracting the immersed length from the initial length:
L = L0 - 0.3L0 = 0.7L0
Calculating the New Frequency
Using the new length of the pipe, we can calculate the new fundamental frequency using the same equation as before:
f' = v / (2L)
Substituting L with 0.7L0:
f' = v / (2 * 0.7L0) = (5/7) * (v / (2L0)) = (5/7) * f
Therefore, the new frequency f' is equal to (5/7) times the initial frequency f.
Conclusion
In conclusion, when 30% of the length of an open organ pipe is immersed in water, the new frequency of the pipe is (5/7) times the initial frequency. This change in frequency is due to the change in effective length caused by the immersion in water.
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fundamental frequency of an open organ pipe is 1400Hz . if its 30% len...
sorry.. calculate its new freq.. of organ pipe .
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fundamental frequency of an open organ pipe is 1400Hz . if its 30% length is immersed in water then calculate new frequency of open organ pipe ? pls explain the ans.
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fundamental frequency of an open organ pipe is 1400Hz . if its 30% length is immersed in water then calculate new frequency of open organ pipe ? pls explain the ans. for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about fundamental frequency of an open organ pipe is 1400Hz . if its 30% length is immersed in water then calculate new frequency of open organ pipe ? pls explain the ans. covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for fundamental frequency of an open organ pipe is 1400Hz . if its 30% length is immersed in water then calculate new frequency of open organ pipe ? pls explain the ans..
fundamental frequency of an open organ pipe is 1400Hz . if its 30% length is immersed in water then calculate new frequency of open organ pipe ? pls explain the ans. for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about fundamental frequency of an open organ pipe is 1400Hz . if its 30% length is immersed in water then calculate new frequency of open organ pipe ? pls explain the ans. covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for fundamental frequency of an open organ pipe is 1400Hz . if its 30% length is immersed in water then calculate new frequency of open organ pipe ? pls explain the ans..
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