Calculating the Speed of Moving Protons in a Magnetic Field

Introduction:
In this question, we are given a magnetic field of 0.06 T and an electric field of 9000 V/m. We are required to find the speed of the moving protons.

Formula:
The force experienced by a charged particle moving in a magnetic field is given by the formula F = qvB, where F is the force, q is the charge, v is the velocity, and B is the magnetic field strength.

Calculations:
We know that the protons are passing through the magnetic field without deflection. This means that the magnetic force is being balanced by the electric force.

The force experienced by the protons due to the magnetic field is given by F = qvB. The force experienced by the protons due to the electric field is given by F = Eq, where E is the electric field strength and q is the charge of the proton.

Since the forces are balanced, we can equate these two equations and get the value of the velocity of the protons.

qvB = Eq

v = E/B

Substituting the values of E and B, we get

v = 9000/0.06

v = 150,000 m/s

Therefore, the speed of the moving protons is 150,000 m/s.

Explanation:
The question required us to find the speed of the moving protons in a magnetic field. We used the formula for the force experienced by a charged particle in a magnetic field to calculate the velocity of the protons. Since the protons were not deflected by the magnetic field, we knew that the magnetic force was being balanced by the electric force. We equated the two forces and solved for the velocity of the protons. The final answer was 150,000 m/s.

We know that :-->
Eq = VqB (Where , E = electric field , q = charge on proton , V = Speed of moving proton , B = magnetic field)
So, V= E/B = 9000/0.06 = 150 × 10^3 m/s ...ans...

$$Hope it's help... $$