Graph of Potential Difference vs Current

To plot the graph of potential difference V against current I, we will use the given values of current and potential difference. The current values are given in amperes (A) and the potential difference values are given in volts (V).

The table below shows the given values:

I (A) | V (V)
--------------
0.5 | 1.6
1.0 | 3.4
2.0 | 6.7
3.0 | 10.2
4.0 | 13.2

We will plot these values on a graph, with the current (I) on the x-axis and the potential difference (V) on the y-axis.

Calculating Resistance

The resistance (R) of the resistor can be calculated using Ohm's Law, which states that the potential difference across a resistor is directly proportional to the current flowing through it. Mathematically, Ohm's Law is expressed as:

V = IR

where V is the potential difference, I is the current, and R is the resistance.

To calculate the resistance, we can rearrange the equation to solve for R:

R = V/I

Using the given values of potential difference and current, we can calculate the resistance for each corresponding pair of values. The resistance values are calculated as follows:

For I = 0.5 A and V = 1.6 V:
R = V/I = 1.6/0.5 = 3.2 Ω

For I = 1.0 A and V = 3.4 V:
R = V/I = 3.4/1.0 = 3.4 Ω

For I = 2.0 A and V = 6.7 V:
R = V/I = 6.7/2.0 = 3.35 Ω

For I = 3.0 A and V = 10.2 V:
R = V/I = 10.2/3.0 = 3.4 Ω

For I = 4.0 A and V = 13.2 V:
R = V/I = 13.2/4.0 = 3.3 Ω

Plotting the Graph

Now, let's plot the graph using the calculated resistance values. The x-axis represents the current (I) and the y-axis represents the potential difference (V).

The graph shows a linear relationship between the values of current and potential difference, indicating that the resistor obeys Ohm's Law. The resistance of the resistor can be determined by finding the slope of the line on the graph.

Conclusion

From the graph, we can see that the potential difference (V) is directly proportional to the current (I), indicating that the resistor follows Ohm's Law. The resistance of the resistor is calculated to be approximately 3.35 Ω using the given values.