**Introduction**
When a current flows through a wire, it creates a magnetic field around it. The strength of the magnetic field depends on the magnitude and direction of the current, as well as the distance from the wire. In this question, we are asked to find the magnetic field at a point lying on a perpendicular to the wire, drawn through the point of bending, at a distance d from it.

**Solution**
To solve this problem, we can use the Biot-Savart law, which gives the magnetic field at a point due to a small element of current. The law is given by:

dB = μ0/4π * (idl x r) / r^3

where dB is the magnetic field at the point due to the small element of current idl, r is the distance from the element to the point, and μ0 is the permeability of free space.

We can divide the wire into two straight sections, and then consider the magnetic field due to each section separately. Let the sections be labeled 1 and 2, with section 1 lying in the x-z plane, and section 2 lying in the y-z plane. The point of bending is at the origin.

**Magnetic field due to section 1**
Consider a small element of length dl on section 1, located at a distance x from the origin. The current in this element is i, and the distance from the element to the point P is r = √(x^2 + d^2). The direction of the magnetic field due to this element is perpendicular to both idl and r, and is given by the right-hand rule. Using the Biot-Savart law, we can calculate the magnetic field due to this element as:

dB1 = μ0/4π * (idl x r) / r^3

= μ0/4π * (i dl x (x i + d j)) / (x^2 + d^2)^(3/2)

= μ0/4π * i dl / (x^2 + d^2)^(3/2) * (-d i + x j)

The total magnetic field due to section 1 is obtained by integrating over the entire length of the section. Since the section lies in the x-z plane, the i component of dB1 is cancelled out by the i component of the next element of length dl. Therefore, we only need to integrate over the j component of dB1. The integral can be written as:

B1 = ∫dB1 = μ0/4π * i ∫dl / (x^2 + d^2)^(3/2) * x

= μ0/4π * i (1 / d - 1 / (d + L)) * j

where L is the total length of section 1.

**Magnetic field due to section 2**
Consider a small element of length dl on section 2, located at a distance y from the origin. The current in this element is i, and the distance from the element to the point P is r = √(y^2 + d^2). The direction of the magnetic field due to this element is perpendicular to both idl and r, and is given by the right-hand rule. Using the Biot-Savart law, we can calculate the magnetic field due to this element as:

dB