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Two identical conducting balls having positive charges q1 and q2 are separated by a centre to centre distance r . If they are made to touch each other and then separated to the same distance the force between them will be A ) less than before B ) same as before C ) more than before D ) zero?
Most Upvoted Answer
Two identical conducting balls having positive charges q1 and q2 are s...
Answer:
Explanation:
When two identical conducting balls having positive charges q1 and q2 are separated by a centre to centre distance r, the force between them is given by Coulomb's law as:
F = (1/4πε) * (q1q2/r²)
where ε is the permittivity of free space.
When the two balls are made to touch each other, their charges get redistributed and they acquire a common potential. Let this potential be V. Then, the charges on the two balls will be q1' = q2' = q1 + q2.
When the balls are separated to the same distance r, their charges remain the same but the distance between them decreases to r/2. Therefore, the force between them is given by:
F' = (1/4πε) * [(q1+q2)²/(r/2)²] = (1/4πε) * 4(q1+q2)²/r² = (1/4πε) * 4(q1²+2q1q2+q2²)/r²
= (1/4πε) * (q1q2/r²) * 4(q1/q2 + 2 + q2/q1 + 2) = 4F * (q1/q2 + 2 + q2/q1 + 2)
From the above equation, we can see that:
- If q1 = q2, then F' = 8F, which means the force between the balls is more than before.
- If q1 > q2, then q1/q2 > 1 and q2/q1 < 1,="" which="" means="" f'="" /> F, and the force is more than before.
- If q1 < q2,="" then="" q1/q2="" />< 1="" and="" q2/q1="" /> 1, which means F' < f,="" and="" the="" force="" is="" less="" than="" />
Therefore, the correct answer is option A) less than before.
Explanation:
When two identical conducting balls having positive charges q1 and q2 are separated by a centre to centre distance r, the force between them is given by Coulomb's law as:
F = (1/4πε) * (q1q2/r²)
where ε is the permittivity of free space.
When the two balls are made to touch each other, their charges get redistributed and they acquire a common potential. Let this potential be V. Then, the charges on the two balls will be q1' = q2' = q1 + q2.
When the balls are separated to the same distance r, their charges remain the same but the distance between them decreases to r/2. Therefore, the force between them is given by:
F' = (1/4πε) * [(q1+q2)²/(r/2)²] = (1/4πε) * 4(q1+q2)²/r² = (1/4πε) * 4(q1²+2q1q2+q2²)/r²
= (1/4πε) * (q1q2/r²) * 4(q1/q2 + 2 + q2/q1 + 2) = 4F * (q1/q2 + 2 + q2/q1 + 2)
From the above equation, we can see that:
- If q1 = q2, then F' = 8F, which means the force between the balls is more than before.
- If q1 > q2, then q1/q2 > 1 and q2/q1 < 1,="" which="" means="" f'="" /> F, and the force is more than before.
- If q1 < q2,="" then="" q1/q2="" />< 1="" and="" q2/q1="" /> 1, which means F' < f,="" and="" the="" force="" is="" less="" than="" />
Therefore, the correct answer is option A) less than before.
Community Answer
Two identical conducting balls having positive charges q1 and q2 are s...
More than before
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Two identical conducting balls having positive charges q1 and q2 are separated by a centre to centre distance r . If they are made to touch each other and then separated to the same distance the force between them will be A ) less than before B ) same as before C ) more than before D ) zero?
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Two identical conducting balls having positive charges q1 and q2 are separated by a centre to centre distance r . If they are made to touch each other and then separated to the same distance the force between them will be A ) less than before B ) same as before C ) more than before D ) zero? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two identical conducting balls having positive charges q1 and q2 are separated by a centre to centre distance r . If they are made to touch each other and then separated to the same distance the force between them will be A ) less than before B ) same as before C ) more than before D ) zero? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two identical conducting balls having positive charges q1 and q2 are separated by a centre to centre distance r . If they are made to touch each other and then separated to the same distance the force between them will be A ) less than before B ) same as before C ) more than before D ) zero?.
Two identical conducting balls having positive charges q1 and q2 are separated by a centre to centre distance r . If they are made to touch each other and then separated to the same distance the force between them will be A ) less than before B ) same as before C ) more than before D ) zero? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two identical conducting balls having positive charges q1 and q2 are separated by a centre to centre distance r . If they are made to touch each other and then separated to the same distance the force between them will be A ) less than before B ) same as before C ) more than before D ) zero? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two identical conducting balls having positive charges q1 and q2 are separated by a centre to centre distance r . If they are made to touch each other and then separated to the same distance the force between them will be A ) less than before B ) same as before C ) more than before D ) zero?.
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